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GaryK [48]
3 years ago
11

Find two consecutive integers such that the sum of their squares is 421

Mathematics
1 answer:
MariettaO [177]3 years ago
4 0
The answer is 14 and 15 because 14 squared is 196 and 15 squared is 225 and those added would give you the 421.
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(5x-1)(3x+2)(9x-4) simply
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Answer:

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Step-by-step explanation:

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= 135x^3 + 3x^2 - 46x + 8.

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