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cupoosta [38]
3 years ago
8

(20 Points)

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
Between step 2 and step 3 emily subtracted 2 instead of adding 2
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(0,65-3,21)por(-8,12)=?
PIT_PIT [208]

Answer:  =20,7872

Step-by-step explanation:

For this exercise it is important to remember the multiplication of signs. Notice that:

(+)(+)=+\\\\(-)(-)=+\\\\(-)(+)=-\\\\(+)(-)=-

In this case you have the following expression given in the exercise:

(0,65-3,21)(-8,12)

Then you can follow the steps shown below in order to solve it:

Step 1: You must solve the subtraction of the numbers 0,65 and 3,21. Then:

=(-2,56)(-8,12)

Step 2: Now you must find the product of the decimal numbers above. In order to do that you must multiply the numbers.

(As you can notice, both are negative, therefore you know that the product will be positive).

Then, you get that the result is the following:

 =20,7872

5 0
3 years ago
The perimeter of a triangle is 29. One side of a triangle is 5 less than twice the side of the shortest length. The third side i
PolarNik [594]

Answer:

  • 7, 9, 13

Step-by-step explanation:

Let the sides of the triangle be a, b and c.

<u>We have:</u>

  • P = a + b + c = 29
  • a = 2b - 5
  • c = b + 6

<u>Substitute values and solve for b:</u>

  • 2b - 5 + b + b + 6 = 29
  • 4b + 1 = 29
  • 4b = 28
  • b = 7

<u>Find a and c:</u>

  • a = 2*7 - 5 = 14 - 5 = 9
  • c = 7 + 6 = 13

<u>The sides are:</u> 7, 9, 13

4 0
3 years ago
Read 2 more answers
I dont get it i tried working on it and its hard
olga55 [171]
On the cube, it measures in numerical order 1 to 6, so:
1,2,3,4,5,6.
We are finding how much red fabric was used for even numbered sides.

So we are looking for sides 2,4,6

Since 20 in. is measured on a side, we can determine the area: 20*2= 40 in.^2 (all sides are same and length*width)

Now we have how much fabric is used on each side, so apply the area to all the even numbers (2,4,6)

40*3= 120 inches
3 0
4 years ago
Bethany opened a store credit card to purchase a TV for $589. She put the entire purchase on the credit card. Her APR is 29.99%
7nadin3 [17]
Original debt = $589
APR = 29.99%
The monthly rate is 0.2999/12 = 0.02499

After 1 month:
Amount owed = 589*1.02499 = $603.72
5% payment = 0.05*603.72 = $30.187
New balance = $603.72 - 30.187 = $573.53

After 2 months:
Amount owed = 573.53*1.02499 = $587.87
5% payment = 0.05*587.87 = $29.39
New balance = 587.87 - 29.39 = $558.48

After 3 months:
Amount owed = 558.48*1.02499 = $572.44
5% payment = 0.05*572.44 = $28.62
New balance = 572.43 - 28.62 = $543.82

Answer: $543.82

4 0
3 years ago
Find the quadratic function passing through the points (0,-3), (1,2), and (2,-1)
user100 [1]

<u>Answer:</u>

The quadratic function passing through the points (0,-3), (1,2), and (2,-1) is \mathrm{f}(\mathrm{x})=-4 x^{2}+9 x-3

<u>Solution: </u>

Given that required function is quadratic  

And function is passing through points (0 , -3) , (1 , 2) and (2 , -1)

General form of a quadratic function is  f(x)=a x^{2}+b x+c ----(A)

f(x) is nothing but output value that is y.

That is f(x) = y

So y=a x^{2}+b x+c  --- (1)

Let’s use equation (1) to get required function.

Given that function passes through (0 , -3) means when x = 0 , y = -3

On substituting value of x and y in equation (1) we get  

-3=\mathrm{a}(0)^{2}+\mathrm{b}(0)+\mathrm{c}

-3 = 0 + 0 + c

c = -3

On substituting value of c in equation (1) we get  

y=a x^{2}+b x-3 ---(2)

Function also passes through point (1, 2) that is at x = 1 , y = 2.

On substituting value of x and y in equation (2) we get  

2=\mathrm{a}(1)^{2}+\mathrm{b}(1)-3

2 = a + b – 3

a + b = 5                

b = 5 - a   -------(3)

Also given function passes through point ( 2 , -1) means when x = 2 , y = -1

On substituting value of x and y in equation (2) we get  

-1=\mathrm{a}(2)^{2}+\mathrm{b}(2)-3

-1 = 4a + 2b – 3

4a + 2b = 2

2a + b = 1  ------- (4)

On substituting value of b from equation (3) in equation (4), we get

2a + (5 - a ) = 1  

a + 5 = 1

a = 1-5 = -4

From equation (3) b = 5 – a = 5 – (-4) = 9

b = 9

Now we have a = -4, b = 9 and c = -3

On substituting calculated values of a, b, and c in equation (A) we get

f(x)=-4 x^{2}+9 x-3

Hence required quadratic function is f(x)=-4 x^{2}+9 x-3

8 0
3 years ago
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