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3 years ago

In 8+4=12, the 8 and 4 are

Mathematics

2 answers:

Alina [70]3 years ago

8 0

8 - 1st term

4 - 2nd term

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P.S. Hello from Russia :^)

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Nimfa-mama [501]3 years ago

3 0

Answer:

equaled to 12

Step-by-step explanation:

lol they're the addends

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Jlenok [28]

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2 years ago

Read 2 more answers

What is the weight, in Newtons, of a person on Earth whose mass is 90 kilograms? Gravity near the Earth's surface is 9.8 m/s2.

valentinak56 [21]

Answer:

W = 882 N

Step-by-step explanation:

Given that,

The weight of a person, W = 90 kg

The value of acceleration due to gravity, g = 9.8 m/s²

We need to find the weight of the person on Earth. The formula for the weight of an object is given by :

W = mg

Substitute all the values,

W = 90 kg × 9.8 m/s²

W = 882 N

So, the weight of the person is equal to 882 N.

8 0

3 years ago

A summer camp is organizing a hike and needs to buy granola bars for the campers. The granola bars come in small boxes and large

Irina18 [472]

Answer:

The Answer is: There are 8 small boxes and 9 large boxes. See explanation below for variables and variable definitions.

Step-by-step explanation:

Let s = small boxes. Let b = large boxes.

s + b = 17

You can solve for s:

s = 17 - b

You can solve for b:

b = 17 - s

10 times the number of small boxes plus 24 times the number of large boxes is equal to 296 granola bars.

10s + 24b = 296

Substitute:

10(17 - b) + 24b = 296

170 - 10b + 24b = 296

14b = 296 - 170

14b = 126

b = 126 / 14 = 9 large boxes

Find the number of small boxes, s:

s = 17 - b = 17 - 9 = 8 small boxes

There are 8 small boxes and 9 large boxes.

Proof:

10(8) + 24(9) = 296

80 + 216 = 296

296 = 296

4 0

3 years ago

Sunny_sXe [5.5K]

I’m assuming a. Or 26 since it’s the only number within the range

7 0

3 years ago

The surface area of a cylinder is increasing at a rate of 9 pi square meters per hour. The height of the cylinder is fixed at 3

Alekssandra [29.7K]

Answer:

$9\pi \text{ cubic meters per hour}$

Step-by-step explanation:

Since, the surface area of a cylinder,

$A= 2\pi r^2 + 2\pi rh$ ................(1)

Where,

r = radius,

h = height,

If $A= 36\pi\text{ square meters}, h = 3\text{ meters}$

$36\pi = 2\pi r^2 + 2\pi r(3)$

$18 = r^2 + 3r$

$\implies r^2 + 3r - 18=0$

$r^2 + 6r - 3r - 18 = 0$ ( by middle term splitting )

$r(r+6)-3(r+6)=0$

$(r-3)(r+6)=0$

By zero product property,

r = 3 or r = - 6 ( not possible )

Thus, radius, r = 3 meters,

Now, differentiating equation (1) with respect to t ( time ),

$\frac{dA}{dt}= 4\pi r\frac{dr}{dt} +2\pi(r\frac{dh}{dt} + h\frac{dr}{dt})$

∵ h = constant, ⇒ dh/dt = 0,

$\frac{dA}{dt} = 4\pi r \frac{dr}{dt} +2\pi h \frac{dr}{dt}$

We have, $\frac{dA}{dt}=9\pi\text{ square meters per hour}, r = h = 3\text{ meters}$

$9\pi = 4\pi (3) \frac{dr}{dt}+2\pi (3)\frac{dr}{dt}$

$9\pi = (12\pi + 6\pi )\frac{dr}{dt}$

$9\pi = 18\pi \frac{dr}{dt}$

$\implies \frac{dr}{dt} =\frac{1}{2}\text{ meter per hour}$

Now,

Volume of a cylinder,

$V=\pi r^2 h$

Differentiating w. r. t. t,

$\frac{dV}{dt}=\pi ( r^2 \frac{dh}{dt}+h(2r)\frac{dr}{dt})=\pi ((3)(6) (\frac{1}{2})) = 9\pi \text{ cubic meters per hour}$

6 0

3 years ago