The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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I’m sorry i don’t speak Spanish!
Answer:
thats a right triangle
Step-by-step explanation:
because of the little square that is in the one corner telling you that is 90 degrees or a right angle.
Let U={q, r, s, t, u, V, W, X, Y, Z},
trapecia [35]
Answer:
Ooh is theis unions I did it but
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<span>(t) = 0 gives
</span><span>-24t + 60 = 0
</span><span>t = 2.5
</span><span>For this t, the second derivative s"(t) = -24 is negative. And so, s(t) is maximum for t = 2.5.
</span><span>Maximum height is S = -12(2.5)^2 + 60(2.5) +8 = 233ft</span>
