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3 years ago

Given the equation 4x+7=3(2x-5), solve for the variable

Mathematics

1 answer:

ryzh [129]3 years ago

3 0

4x+7=3(2x-5)
4x+7 = 5x-15
-x+7= -15
-x=-22
x=22

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dalvyx [7]

Answer:

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Step-by-step explanation:

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3 years ago

I need help 5=6(1q-5)-19

Rudiy27

ok distribute the 6 by multiplying it by 1q and -5
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AURORKA [14]

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$\boxed{235}$

Step-by-step explanation:

Hey there!

Well given that,

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10(25) - 5(3)

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Find the average value of the function on the given interval. f(x)=2 ln x; [1,e]

JulijaS [17]

Answer:

$f_{avg}=\frac{1}{e-1}$

Step-by-step explanation:

We are given that a function

$f(x)=2lnx$

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx$

By Parts integration formula

$\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx$

u=ln x and v=dx

Apply by parts integration

$f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))$

$f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})$

$f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}$

By using property lne=1,ln 1=0

$f_{avg}=\frac{1}{e-1}$

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3 years ago