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3 years ago

Element of sample space for shooting 2 free throws in basketball

1 answer:

4 0

An "element" of a sample space is a possible outcome in the sample space. It's possible to make both shots , it's possible to miss both shots.

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What is the slope of the line in the graph?

Goshia [24]

Answer:

My answer would be y=2x+1

Step-by-step explanation:

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3 years ago

Exactly 1 1/3 yard of ribbon is needed to make a bow. Which of the following lengths of ribbon could be used to make a bow with

svp [43]

Answer:

1 and 2/5 yards wastes only 1/15 a yard

Step-by-step explanation:

1 and 1/6 yards would make a waste of 1 and 1/6 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/10 yards would make a waste of 1 and 1/5 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/5 yards

$1\frac{2}{5} -1\frac{1}{3} =\\\\1\frac{6}{15} -1\frac{5}{15} =\\\\\frac{1}{15}$

Wastes 1/15 a yard.

1 and 1/2 yards

$1\frac{1}{2} -1\frac{1}{3} =\\\\1\frac{3}{6} -1\frac{2}{6} =\\\\\frac{1}{6}$

It wastes 1/6 a yard.

2 yards

$2-1\frac{1}{3} =\frac{2}{3}$

It wastes 4/6 a yard.

4 0

3 years ago

WILL MAKE BRAINLIEST!!

Grace [21]

Here you go
1) -1
2)-4,4

5 0

3 years ago

Read 2 more answers

_____ represent numerical data by varying the thickness and pattern of vertical lines.

Georgia [21]

The answer is
Bar codes

4 0

3 years ago

The Patterson family has 3 kids, 1 boy and 2 girls. Suppose that for each birth, the probability of a boy birth is 1/2, and the

elena-14-01-66 [18.8K]

Answer:

$Probability = \frac{1}{8}$

Step-by-step explanation:

Given

Represent Boys with B and Girls with G

$P(B) = \frac{1}{2}$

$P(G) = \frac{1}{2}$

Required

Find the probability or having 1 boy 2 girls

Since the order is not important, the probability is calculated as follows;

$Probability = P(B) * P(G) * P(G)$

Substitute $\frac{1}{2}$ for P(B) and P(G)

$Probability = \frac{1}{2} * \frac{1}{2} * \frac{1}{2}$

$Probability = \frac{1 * 1 * 1}{2 * 2 *2}$

$Probability = \frac{1}{8}$

Hence, the fractional probability is $\frac{1}{8}$

7 0

3 years ago