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andriy [413]
3 years ago
5

WILL MARK BRAINLIEST! A fruit mixture requires for 4 oranges for every 3 apples. How many oranges do you need if you have 12 app

les?
Mathematics
2 answers:
Murrr4er [49]3 years ago
7 0

Answer:

16 oranges

Step-by-step explanation:

For every apple you have one more orange. You could divide 12 by 3 an you would get 4. so you add 4 more to 12 and you get 16 oranges. Or you could just multiply 4 by 4.

arlik [135]3 years ago
3 0

Answer:

9 oranges

Step-by-step explanation:

4 oranges for every 3 apples

8 oranges for every 6 apples

12 oranges for every 9   apples

Do you see the relationship here? 4 x 2 = 8         4 x 3 = 12       3 x 2 = 6    3 x 3 = 9

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Please look at picture
Natasha2012 [34]

Answer:

32%

The probability according to these results is 32% because 25 people ordered a cold drink. 8 of those were smalls. 8 divided by 25 is 0.32 which is the percentage of a 100% chance aka 32%

6 0
2 years ago
Correct answers only please!
-Dominant- [34]

Answer:

63.4

Step-by-step explanation:

The triangle is right angled , so :

tan S = UT/ST

tan S = 2/1

tan S = 2

S = tan^{-1}2

S = 63.4

5 0
3 years ago
Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)
ElenaW [278]

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

3 0
1 year ago
Read 2 more answers
What is the product of 4 2/3 and 11 1/4
mihalych1998 [28]

First you have to get rid of the mixed numbers, so multiply the whole numbers with the denominators and add the numerators so that way you get:

14/3 times 45/4....then cross simplify if possible and finally you can multiply the numerators and the denominators...

7/1 times 15/2 = 105/2....simplify it and get: 52 1/2


7 0
3 years ago
10^(-10log3) How to solve this???
Olenka [21]
a^{log_ab}=b\\and\\log_ab^c=c\cdot log_ab\\\\\\10^{-10log3}=10^{log3^{-10}}=3^{-10}\\\\\\3^{-10}=\frac{1}{3^{10}}=\frac{1}{59\ 049}
4 0
3 years ago
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