14+14=28
48-28=20
20 divided by 2 =10
The width is 10
Step-by-step explanation:
x+30°=4x(inscribed angle is equal to its arc)
4x-x=30°
3x=30°
x=30/3
x=10°
hope it helps.
Solve for x
-53 + 8x = 3x + 47
8x - 3x = 47 + 53
5x = 100
x = 20
Answer:
The correct answer is Option B: Quadrants II and III have negative x-coordinates.
Just FYI: Quadrants II and III have both positive and negative y-coordinates.
Answer:
Step-by-step explanation:
f(2) = 0
