Answer:
-3+2sqrt7
-3-2sqrt7
Step-by-step explanation:
x^2+6x-9=10
x^2+6x-9-10=0
x^2+6x-19=0
ax^2+bx+c=0
a=1 b=6 c=-19
As cannot be solved by completing square we will use quadratic equation
x= (-b+sqrt(b^2-4ac))/2a and x= (-b-sqrt(b^2-4ac))/2a
x= (-6+sqrt(6^2-4*-19))/2 and x= (-6-sqrt(6^2-4*-19))/2
x=(-6+sqrt(36+76))/2 and x=(-6-sqrt(36+76))/2
x=(-6+4sqrt7)/2 and x=(-6-4sqrt7)/2
x=(-3+2sqrt7) and x=(-3-2sqrt7)
x=2.29 and x= -8.29
Answer:
b
Step-by-step explanation:
Answer:
Part 1) The inequality that represent this situation is
or ![5x^{2}+70x+245 \geq1,050](https://tex.z-dn.net/?f=5x%5E%7B2%7D%2B70x%2B245%20%5Cgeq1%2C050)
Part 2) Yes, 8 inches is a reasonable width for his tablet
Step-by-step explanation:
Part 1)
Let
L -----> the length of the screen television
W ----> the width of the screen television
x ----> the width of Andrew's tablet
we know that
------> equation A
----> equation B
The area of the television is
-----> equation C
Substitute equation A and equation B in equation C
![A=5(x+7)^{2}](https://tex.z-dn.net/?f=A%3D5%28x%2B7%29%5E%7B2%7D)
------> inequality that represent this situation
Part 2) Determine if 8 inches is a reasonable width for his tablet
For x=8 in
Substitute in the inequality
![5(8+7)^{2} \geq1,050](https://tex.z-dn.net/?f=5%288%2B7%29%5E%7B2%7D%20%5Cgeq1%2C050)
![5(15)^{2} \geq1,050](https://tex.z-dn.net/?f=5%2815%29%5E%7B2%7D%20%5Cgeq1%2C050)
-----> is true
therefore
Yes, 8 inches is a reasonable width for his tablet
Using the pairs (1,32) and (2,64) the rate of speed is (64-32 / 2-1 = 32 feet per second.
To find the rate of decent you would multiply the rate by time:
The equation is y = 32x
B. Replace x with 15 and solve for y:
Y = 32(15)
Y = 480
The rate of speed is 480 feet per second.