2 years ago

Glenn invested $22,000 at 7% interest compounded annually. How much interest will Glenn earn in 3 years?

Mathematics

1 answer:

Eva8 [605]2 years ago

7 0

$26,950.95 would be the answer.........

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How do you find the limit of (2+x)^3 -8/x as the limit approaches 0? Please explain how you did it.

RoseWind [281]

Answer: 12

<u>Step-by-step explanation:</u>

Expand (2 + x)³, factor out the x, then replace x with zero.

$(x+2)^3 = (x+2)(x+2)(x+2)\\.\qquad \quad =(x+2)(x^2+4x+4)\\.\qquad \quad =x(x^2+4x+4)+2(x^2+4x+4)\\.\qquad \quad =x^3+4x^2+4x\quad +2x^x+8x+8\\.\qquad \quad =x^3+(4x^2+2x^2)+(4x+8x)+8\\.\qquad \quad =x^3+6x^2+12x+8$

$\dfrac{(x+2)^3-8}{x}=\dfrac{(x^3+6x^2+12x+8)-8}{x}=\dfrac{x^3+6x^2+12x}{x}\\\\\\=\dfrac{x(x^2+6x+12)}{x}=x^2+6x+12\\\\\\ \lim_{x \to 0} \quad x^2+6x+12\quad =\quad 0+0+12\quad =\quad \large\boxed{12}$