Answer:
A) C=6t
Step-by-step explanation:
Answer:
<u>Q/ Draw a line ; Ans; </u>

*explain ; We put the 5 in the denominator and 5 multiply 1 + 4 so equal 9 so the choice 9/5 .
Ans; 7/3—> 2 1/3
*explain ; We put the 3 in the denominator and 3 multiply 2 + 1 so equal 7 so the choice 7/3 .
Ans; 12/10 —> 1 1/5
*explain; simple (12 and 10) ÷ 2 so equal 6/5
We put the 5 in the denominator and 5 multiply 1 + 1 so equal 6 so the choice 6/5 =12/10 .

<u>Q/ Compare the fractions;Ans;</u>

* explain; 2/3 = 0.66 and 14/6=2.33 so 2.33 greater from 0.66 so 14/6 greater from 2/3 .

* explain; 3/8 = 0.375 and 8/3=2.666 so 2.666 greater from 0.375 so 8/3 greater from 3/8 .

* explain; 2 1/6 —> We put the 6 in the denominator and 6 multiply 2 + 1 so equal 13 so equal 13/6
13/6 = 2.16 and 5/9=0.55 so 2.16 greater from 0.55 so 13/6 = 2 1/6 greater from 5/9 .
<u>Q/Add; Ans;</u>


<u>Q/Subtract; Ans;</u>


<u>Q/ Multiply;Ans;</u>


<u>Q/Divide;Ans;</u>


I hope I helped you^_^
Answer:
2/7
Step-by-step explanation:
You have to flip the fraction to check, you see what times 3 gets you six... 2!
then what times one gets you 7.. 7! and that how you get 3/7
Answer:
C) x ≥ 11 or x ≤ -3
Explanation:
Given following: |x − 4| ≥ 7
Apply absolute rule: If |u| ≥ 0 then u ≤ -a, u ≥ a
Solving stepwise:
⇒ x - 4 ≤ -7, x - 4 ≥ 7
<u>change sides</u>
⇒ x ≤ -7 + 4, x ≥ 7 + 4
<u>add/subtract integers</u>
⇒ x ≤ -3, x ≥ 11
We need to see the the picture of the problem to be able to help you! :)