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Alina [70]
3 years ago
10

Hi I need this asap if you also explain the work on how you got answers plz and thank you​

Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0

Answer:

<u>Q/ Draw a line ; Ans; </u>

\frac{9}{5}  —>1 \frac{4}{5}

*explain ; We put the 5 in the denominator and 5 multiply 1 + 4 so equal 9 so the choice 9/5 .

Ans; 7/3—> 2 1/3

*explain ; We put the 3 in the denominator and 3 multiply 2 + 1 so equal 7 so the choice 7/3 .

Ans; 12/10 —> 1 1/5

*explain; simple (12 and 10) ÷ 2 so equal 6/5

We put the 5 in the denominator and 5 multiply 1 + 1 so equal 6 so the choice 6/5 =12/10 .

\frac{12 \div 2}{10 \div 2}  =  \frac{6}{5}  = 1 \frac{1}{5}

<u>Q/ Compare the fractions;Ans;</u>

\frac{2}{3}  <  \frac{14}{6}

* explain; 2/3 = 0.66 and 14/6=2.33 so 2.33 greater from 0.66 so 14/6 greater from 2/3 .

\frac{3}{8}  <  \frac{8}{3}

* explain; 3/8 = 0.375 and 8/3=2.666 so 2.666 greater from 0.375 so 8/3 greater from 3/8 .

2  \frac{1}{6}  >  \frac{5}{9}

* explain; 2 1/6 —> We put the 6 in the denominator and 6 multiply 2 + 1 so equal 13 so equal 13/6

13/6 = 2.16 and 5/9=0.55 so 2.16 greater from 0.55 so 13/6 = 2 1/6 greater from 5/9 .

<u>Q/Add; Ans;</u>

\frac{7}{8}  +  \frac{5}{8}  =  \frac{7 + 5}{8}  =  \frac{12}{8}  =  \frac{3}{2}

\frac{1}{9}  +  \frac{2}{3}  \\  \\  \frac{1}{9}  +  \frac{6}{9}  =  \frac{ 1+6 }{9}  =  \frac{7}{9}

<u>Q/Subtract; Ans;</u>

\frac{6}{7}  -  \frac{4}{7}  =  \frac{6 - 4}{7}  =  \frac{2}{7}

\frac{7}{3}  -  \frac{2}{9}  \\  \\  \frac{21}{9}  -  \frac{2}{9}  =  \frac{21 - 2}{9}  =  \frac{19}{9}

<u>Q/ Multiply;Ans;</u>

\frac{1}{5}  \times  \frac{1}{2}  =  \frac{1}{10}

\frac{2}{3}  \times  \frac{3}{8}  =  \frac{6}{24}  =  \frac{1}{4}

<u>Q/Divide;Ans;</u>

\frac{3}{4}  \div  \frac{2}{5}  \\  \\  \frac{3}{4}  \times  \frac{5}{2}  =  \frac{15}{8}

\frac{8}{9}  \div  \frac{1}{3}  \\  \\  \frac{8}{9}  \times  \frac{3}{1} =   \frac{24}{9}  =  \frac{8}{3}

I hope I helped you^_^

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The equation of the tangent line to the circle passing through the point P is; y = (1/√3)x ± 2/√3

<h3>How to find the equation of the tangent?</h3>

I) We are given the equation of the circle as;

x² + y² = 1

Since angle of inclination is 30°, then slope is;

m = tan 30 = 1/√3

Then equation of the tangent will be;

y = (1/√3)x + c

Put  (√3)x + c into the given circle equation to get;

x² + ((1/√3)x + c)² = 1

x² + ¹/₃x² +  (2/√3)cx + c² = 1

⁴/₃x² +  (2/√3)x + (c² - 1) = 0

Since we need to find value of c for equation to become tangent, then the above quadratic equation must have real and equal roots.

Thus;

((2/√3)c)² - 4(⁴/₃)(c² - 1) = 0

⁴/₃c² - ¹⁶/₃(c² - 1) = 0

⁴/₃c² - ¹⁶/₃c² + ¹⁶/₃ = 0

4c² = ¹⁶/₃

c² = ⁴/₃

c = √⁴/₃

c = ±²/√3

Thus, equation of tangent is;

y = (1/√3)x ± 2/√3

II) Radius from the given equation is 1. Thus, we will use trigonometric ratio to find the x and y intercept;

x-intercept is at y = 0;

0 = (1/√3)x ± 2/√3

-(1/√3)x = ±2/√3

Intercept is positive. Thus;

x = (2/√3)/(1/√3)

x = 1

y - intercept is positive at x = 0;

y = (1/√3)0 ± 2/√3

y = 2/√3

Read more about Equation of tangent at; brainly.com/question/17040970

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