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aleksley [76]
4 years ago
14

Which pair of atomic orbitals has the same energy in a krypton atom?

Chemistry
2 answers:
olganol [36]4 years ago
4 0
3px and 4px the is the answer
lana [24]4 years ago
3 0

Answer:

4pz and 4py

Explanation:

The electron configuration of Kr is:

[Ar] 3d¹⁰ 4s² 4p⁶

4p has 3 subatomic orbitals: 4px, 4py and 4pz

As there are a total of 6 electrons each of the three 4p orbitals have two electrons with opposite spins. Hence 4py and 4pz have equal energy. Option D is correct.  

Option A, 1s and 2s is incorrect, as the energy of the 1st orbital is lower than that of the 2nd orbital.  

Option B, 2s and 2p is incorrect, as the energy of the s suborbital is lower than that of the p, even though they both belong to the same orbital.  

Option C, 3px and 4px is incorrect, as the energy of the 3rd orbital is lower than that of the 4th orbital.  

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Answer:

The mass of 1.00 mol of allicin, rounded to the nearest integer, is 162 g

Explanation:

Allicin is a compound that derivates from the alliin which is produced by the catalyzis of an enzime.

The molecular formula is: C₆H₁₀OS₂.

Let's determine the molar mass which is the mass that corresponds to 1 mol

Molar mass C . 6 + Molar mass H . 10 + Molar mass O + Molar mass S . 2 =

12 g/mol . 6 + 1 g/mol . 10 + 16 g/mol + 32.06 g/mol . 2 =  162.1 g/mol

3 0
3 years ago
A balloon contains 3300 mL of helium gas at 63 °C. What is the final volume, in milliliters, of the gas when the temperature cha
Nesterboy [21]

The final volume : 3.4 L

<h3>Further explanation</h3>

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

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T₂=78+273=351 K

the final volume :

\tt V_2=\dfrac{V_1.T_2}{T_1}\\\\V_2=\dfrac{3300\times 351}{336}\\\\V_2=3447.3~ml\rightarrow 2~sig.~fig.\rightarrow 3.4~L

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A point has no demension.​
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Answer:

A point is a 0-D object, infinitely small.

Explanation:

6 0
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If 6.00 g of the unknown compound contained 0.200 mol of C and 0.400 mol of H, how many moles of oxygen, O, were in the sample?
Arada [10]

Convert moles to mass.

mass C = 0.2 mol * 12 g / mol = 2.4 g

mass H = 0.4 mol * 1 g / mol = 0.4 g

So mass left for O = 6 g – (2.4 g + 0.4 g) = 3.2 g

 

Calculating for moles O given mass:

moles O = 3.2 g / (16 g / mol) = 0.2 moles

 

Answer:

<span>0.2 moles O</span>

8 0
4 years ago
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Match each type of learning to the correct definition.
andreev551 [17]

Answer:

conditioning

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