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Kitty [74]
3 years ago
7

A chiral amine A having the R configuration undergoes Hofmann elimination to form an alkene B as the major product. B is oxidati

vely cleaved with ozone, followed by CH3SCH3, to form CH2═O and CH3CH2CH2CHO. What are the structures of A and B? Indicate stereochemistry where appropriate.

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
3 0

Answer:

The Structure of "B" is alkene.

Explanation:

The compound "A" having R- configuration  and undergoes Hofmann elimination to form an alkene.

The compound "B" on oxidatively cleaving with ozone followed by dimethyl sulfide forms CH_{2}=S and CH_{3}CH_{2}CH_{2}CHO

The structure of "A" and"B" is as follows.

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Explanation:

Given the mass of HCl is ---- 0.50 g

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To determine the pH of the resulting solution, follow the below-shown procedure:

1. Calculate the number of moles of HCl given by using the formula:

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2. Calculate the molarity of HCl.

3. Calculate pH of the solution using the formula:

pH=-log[H^+]

Since HCl is a strong acid, it undergoes complete ionization when dissolved in water.

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Thus, [HCl]=[H^+]

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1. Number of moles of HCl given:

number of moles of a substance=\frac{given mass of the substance}{its molecular mass}\\=0.50g/36.5g/mol\\=0.0137mol

2. Concentration of HCl:

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Answer:

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Explanation:

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