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3 years ago

PLEASE HELP ME . - Simplify the expression (x5)1/9. a - 5x^9 . b - 9x^5 . c - x^ 5/9 . d - x^9/5

Mathematics

1 answer:

Nonamiya [84]3 years ago

6 0

Answer:

Option C) $x^{\frac{5}{9}}$ is correct

Therefore $(x^5)^{\frac{1}{9}}=x^{\frac{5}{9}}$

Step-by-step explanation:

Given expression is

To simplify the given expression :

$(x^5)^{\frac{1}{9}}$

$=(x)^{5\times \frac{1}{9}}$ ( using the property $(a^m)^n=a^{mn}$ )

$=x^{\frac{5}{9}}$

Therefore $(x^5)^{\frac{1}{9}}=x^{\frac{5}{9}}$

Therefore option C) $x^{\frac{5}{9}}$ is correct

Therefore the simplified expression is $x^{\frac{5}{9}}$

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Which of the following is the equation for the graph shown? PLS HELP... NEED ANSWER ASAP

lord [1]

Answer:

D the last one

Step-by-step explanation:

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3 years ago

Help me please. Help me please. Help me please.

Gnesinka [82]

A)
To be similar triangles have to have equal angles
triangle ZDB'
1)angle Z=90 degrees
triangle B'CQ
1) angle C 90 degrees

angle A'B'Q=90
DB'Z+A'B'Q+CB'Q=180, straight angle
DB'Z+90+CB'Q=180
DB'Z+CB'Q=90

triangle ZDB'
DZB'+DB'Z=180-90=90

DB'Z+CB'Q=90
DZB'+DB'Z=90
DB'Z+CB'Q=DZB'+DB'Z
2)CB'Q=DZB' (these angles from two triangles ZDB' and B'CQ )
3)so,angles DB'Z and B'QC are going to be equal because of sum of three angles in triangles =180 degrees and 2 angles already equal.
so this triangles are similar by tree angles
b)
B'C:B'D=3:4
B'D:DZ=3:2
CQ-?
DC=AB=21
DC=B'C+B'D (3+4= 7 parts)
21/7=3
B'C=3*3=9
B'D=3*4=12
B'D:DZ=3:2
12:DZ=3:2
DZ=12*2/3=8
B'D:DZ=CQ:B'C
3:2=CQ:9
CQ=3*9/2=27/2

c)
BC=BQ+QC=B'Q+QC
BQ' can be found by pythagorean theorem

3 0

3 years ago

How many different rectangles can you draw, that has an area of 28 cm sq. ? pls help me

jolli1 [7]

Answer:

You can draw three rectangles:

1- 28 * 1.

2- 14*2

3- 7*4

Step-by-step explanation:

We have a total area of 28. If we use only integer numbers, we can find all the divisors of 28. The possible rectangles will be organized with them, taking into account that the product of them, which means the area should be 28.

28 = 1*2*2*7

We can organize them as follows:

R1: 28 = 1*28

R2: 28 = 2*14

R3: 28 = 4*7

Finally, we can conclude that there are only three possibilities

1- 28 by 1.

2- 14 by 2

3- 7 by4

The perimeters will be:

Perimeter 1 = 2x1 + 2x28 = 58

Perimeter 2 = 2x2 + 2x14 = 32