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Nina [5.8K]
3 years ago
15

Which two tables represent data sets that could be fit to a normal distribution curve? A. value 1 2 3 4 5 6 7 8 9 10 11 percenta

ge 1.5% 2.1% 2.2% 3.3% 3.9% 10.5% 14.1% 14.7% 15.3% 15.9% 16.5%
B. value 1 2 3 4 5 6 7 8 9 10 11 percentage 2.3% 4.4% 6.8% 11.4% 20.2% 27.8% 14.1% 7.6% 3.2% 1.5% 0.7%
C. value 2 3 4 5 6 7 8 9 11 10 C. percentage 19.2% 17.3% 6.9% 5.4% 2.9% 0.8% 2.8% 4.6% 7.3% 15.7% 17.1%
D. value 1 2 3 4. 5 6 7 8 9 10 11 percentage 21.3% 15.1% 14.8% 12.3% 8.1% 7.9% 6.3% 5.5% 4.8% 2.3% 1.6% 1 3 2 4 E.value 5 6 9 8 7 10 11 E. percentage 1.2% 2.9% 3.3% 7.9% 17.1% 35.2% 16.7% 8.4% 4.1% 2.3% 0.9%​
Mathematics
2 answers:
valentinak56 [21]3 years ago
7 0

Answer: i put b and e

Step-by-step explanation:

i got it from the person above me lol

enot [183]3 years ago
3 0

Answer:

B&e

Step-by-step explanation:

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Find the sum. Include all calculations in your answer.
Andreas93 [3]

Answer:

- 2 2/7

Step-by-step explanation:

First, do the conversion:

[-(6*7)+3]/7 = -39/7

[(3*7)+2]/7 = 23/7

Then calculate the result:

23/7 - 39/7 = -16/7 or - 2 2/7

6 0
3 years ago
Help please I’ll give brainliest
Sonja [21]
1/4 because there are 8 letters in vacation and two a’s meaning it’s a 2/8 chance simplify that to 1/4 (25%)
3 0
3 years ago
Read 2 more answers
Is it parallel or is it perpendicular?
zavuch27 [327]
It is parallel, which means that the new line should have the same slope of the given line y=-5/4  x+7
and the slope is the coefficient of x 
so the slope = -5/4
in order to solve this problem we have to know the equation of the slop
slope=  \frac{y-y1}{x-x1}
where (x1,y1) is the point by which the new line passes through 

\frac{-5}{4}=\frac{y-(-4)}{x-1}
\frac{-5}{4}= \frac{y+4}{x-1}
-5(x-1)=4(y+4)
-5x +5=4y+16 (by subtracting 16 from both sides)
-5x -11= 4y (divide both sides by 4)
y= \frac{-5}{4}x - \frac{11}{4} 
4 0
3 years ago
Hi, I need help. so pls help me.
antiseptic1488 [7]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees and totaled $411
saw5 [17]

Answer:

Cost of 1 bushes = a = $9

Cost of 1 tree = b = $73.5

Step-by-step explanation:

Given:

13 bushes and 4 trees cost = $411

Missing;

6 bushes and 2 trees cost = $201

Find:

Value of bushes and tree

Computation:

Cost of 1 bushes = a

Cost of 1 tree = b

So,

13a + 4b = 411 ...........eq1

6a + 2b = 201 ................eq2

From Eq1 and Eq2

Cost of 1 bushes = a = $9

From eq 1

13a + 4b = 411

13(9) + 4b = 411

Cost of 1 tree = b = $73.5

5 0
2 years ago
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