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3 years ago

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Which two tables represent data sets that could be fit to a normal distribution curve? A. value 1 2 3 4 5 6 7 8 9 10 11 percenta

ge 1.5% 2.1% 2.2% 3.3% 3.9% 10.5% 14.1% 14.7% 15.3% 15.9% 16.5%
B. value 1 2 3 4 5 6 7 8 9 10 11 percentage 2.3% 4.4% 6.8% 11.4% 20.2% 27.8% 14.1% 7.6% 3.2% 1.5% 0.7%
C. value 2 3 4 5 6 7 8 9 11 10 C. percentage 19.2% 17.3% 6.9% 5.4% 2.9% 0.8% 2.8% 4.6% 7.3% 15.7% 17.1%
D. value 1 2 3 4. 5 6 7 8 9 10 11 percentage 21.3% 15.1% 14.8% 12.3% 8.1% 7.9% 6.3% 5.5% 4.8% 2.3% 1.6% 1 3 2 4 E.value 5 6 9 8 7 10 11 E. percentage 1.2% 2.9% 3.3% 7.9% 17.1% 35.2% 16.7% 8.4% 4.1% 2.3% 0.9%

2 answers:

valentinak56 [21]3 years ago

7 0

Answer: i put b and e

Step-by-step explanation:

i got it from the person above me lol

enot [183]3 years ago

3 0

Answer:

B&e

Step-by-step explanation:

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Please look at the picture, I need help ASAP.

forsale [732]

See below for the proof that the areas of the lune and the isosceles triangle are equal

<h3>How to prove the areas?</h3>

The area of the isosceles triangle is:

$A_1 = \frac 12r^2\sin(\theta)$

Where r represents the radius.

From the figure, we have:

$\theta = 90$

So, the equation becomes

$A_1 = \frac 12r^2\sin(90)$

Evaluate

$A_1 = \frac 12r^2$

Next, we calculate the length (L) of the chord as follows:

$\sin(45) = \frac{\frac 12L}{r}$

Multiply both sides by r

$r\sin(45) = \frac 12L$

Multiply by 2

$L = 2r\sin(45)$

This gives

$L = 2r\times \frac{\sqrt 2}{2}$

$L = r\sqrt 2$

The area of the semicircle is then calculated as:

$A_2 = \frac 12 \pi (\frac{L}{2})^2$

This gives

$A_2 = \frac 12 \pi (\frac{r\sqrt 2}{2})^2$

Evaluate the square

$A_2 = \frac 12 \pi (\frac{2r^2}{4})$

Divide

$A_2 = \frac{\pi r^2}{4}$

Next, calculate the area of the chord using

$A_3 = \frac 12r^2(\theta - \sin(\theta))$

Recall that:

$\theta = 90$

Convert to radians

$\theta = \frac{\pi}{2}$

So, we have:

$A_3 = \frac 12r^2(\frac{\pi}{2} - \sin(\frac{\pi}{2}))$

This gives

$A_3 = \frac 12r^2(\frac{\pi}{2} - 1)$

The area of the lune is then calculated as:

$A = A_2 - A_3$

This gives

$A = \frac{\pi r^2}{4} - \frac 12r^2(\frac{\pi}{2} - 1)$

Expand

$A = \frac{\pi r^2}{4} - \frac{\pi r^2}{4} + \frac 12r^2$

Evaluate the difference

$A = \frac 12r^2$

Recall that the area of the isosceles triangle is

$A_1 = \frac 12r^2$

By comparison, we have:

$A = A_1 = \frac 12r^2$

This means that the areas of the lune and the isosceles triangle are equal

Read more about areas at:

brainly.com/question/27683633

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1 year ago

Find the m ∠YXZ. Show your Work

Charra [1.4K]

Answer:

∠YXZ = 62°

Step-by-step explanation:

A straight line measures 180 degrees

The angle "8x - 14" PLUS its adjacent angle Z sum up to 180, so we can write:

Z + 8x - 14 = 180

Z = 180 +14 - 8x

Z = 194 - 8x

Sum of 3 angles of a triangle is 180 degrees, thus we can write:

X + Y + Z = 180

3x + 5 + 4x + 194 - 8x = 180

Now, we solve for x:

$3x + 5 + 4x + 194 - 8x = 180\\-x+199=180\\x = 199-180\\x=19$

The measure of ∠YXZ is "3x + 5", we substitute the value of x and find this angle to be:

3x + 5

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Brrunno [24]

Answer:

it would take him to 7 hours drive 504 miles.

Step-by-step explanation:

360 miles → 5 hours

1 miles → (5/360) hours

504 miles → [(5/360)*504] hours

504 miles → 7 hours

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Lucy's final exam has true/false questions, worth 2 points each, and multiple choice questions, worth 3 points each. Let x be th

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True/False questions = 2 points each(x).
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Answer:

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2 years ago

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