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4 years ago

If (a,b) is an ordered pair for x-y=5, is (b,a) also a solution?

1 answer:

5 0

The answer is no. Because solution (a,b) means x=a, y=b.and we have a-b=5. And (b,a) would mean x=b and y=a but then x-y=b-a=-(a-b)=-5≠5. So the pair (b,a) is not a solution.

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7f + g = 5, for f literal equations

DENIUS [597]

Answer:

i don't know what exactly your question is but i believe this is the answer if you are trying to find f. f= -1/7g+5/7

Step-by-step explanation:

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3 years ago

Laurie was scuba diving. Each time she dove 5 feet deeper, she would stop and clear her ears. After Laurie had checked her instr

stepladder [879]

Answer:

Laurie's maximum depth can be represented using the expressions :

(20 × 3) = 60

(3 × 4 × 5) = 60

Step-by-step explanation:

Each depth level at which ears are checked = 5 feets

Each Depth level at which instruments are checked = 20 feets

For Laurie to check her instrument ;

Number of times ears are checked = 20/5 = 4 times

This means that for Laurie to have checked her instrument 3 times :

(4 × 3 × 5) = 60 feets

Therefore, Laurie's maximum depth can be expressed as (4 × 3 × 5) = 60 feets

4 0

2 years ago

Read 2 more answers

Which polynomial represents twice the sum of -5x^2-x+6 and 7x^2+x-1?

elena-14-01-66 [18.8K]

The polynomial that represent twice the sum of $-5x^{2}$ - x +6 and 7 $x^{2}$ + x -1 is : 4 $x^{2}$ +10

<h3>What is a polynomial?</h3>

A polynomial is any algebraic expression that has the least value of the power of its variable as 2.

When the highest value of the polynomial is 2, it is a called a quadratic expression.

Analysis:

2( -5 $x^{2}$ -x +6 + 7 $x^{2}$ +x -1)

2( 2 $x^{2}$ + 5) =

4 $x^{2}$ + 10

In conclusion, the polynomial that represents the above expressions is 4 $x^{2}$ + 10

Learn more about polynomials: brainly.com/question/2833285

#SPJ1

7 0

2 years ago

On their first day of vacation, a family spent $127.92 for meals. The family spent $160.01 for meals the second day. By what amo

ehidna [41]

Answer:

D=32.09

Step-by-step explanation:

160.01-127.92=32.09

5 0

3 years ago

Read 2 more answers

What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n

Yakvenalex [24]

Answer:

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

$-2x^{2} +y=-5$ ----> equation A

$y=-3x^{2} +5$ -----> equation B

solve by substitution

substitute equation B in equation A

$-2x^{2} +(-3x^{2} +5)=-5$

solve for x

$-5x^{2} +5=-5$

$-5x^{2}=-10$

$x^{2}=2$

$x=\pm\sqrt{2}$

<em>Find the value of y</em>

$y=-3x^{2} +5$

For $x=\sqrt{2}$ ----> $y=-3(\sqrt{2})^{2} +5=-1$

For $x=-\sqrt{2}$ ----> $y=-3(-\sqrt{2})^{2} +5=-1$

therefore

The solutions are

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

8 0

4 years ago

Read 2 more answers