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Inessa [10]
2 years ago
15

Laurie was scuba diving. Each time she dove 5 feet deeper, she would stop and clear her ears. After Laurie had checked her instr

uments 3 times, she was at her maximum depth of 60 feet. Which expression best represents Laurie’s maximum depth?
(4) (negative 5) (3)
(Negative 4) (Negative 5) (Negative 3)
(Negative 5) (20) (3)
(Negative 5) (Negative 20) (Negative 3)
Mathematics
2 answers:
Paul [167]2 years ago
5 0
20 because that’s the only one that would get her to 60
stepladder [879]2 years ago
4 0

Answer:

Laurie's maximum depth can be represented using the expressions :

(20 × 3) = 60

(3 × 4 × 5) = 60

Step-by-step explanation:

Each depth level at which ears are checked = 5 feets

Each Depth level at which instruments are checked = 20 feets

For Laurie to check her instrument ;

Number of times ears are checked = 20/5 = 4 times

This means that for Laurie to have checked her instrument 3 times :

(4 × 3 × 5) = 60 feets

Therefore, Laurie's maximum depth can be expressed as (4 × 3 × 5) = 60 feets

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SpyIntel [72]

Answer:

(3x+20) = 70

Step-by-step explanation:

All vertical or corresponding angles are congruent, aka they equal eachother.

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A 4   cm × 6   cm 4cm×6cmstart color #1fab54, 4, start text, c, m, end text, times, 6, start text, c, m, end text, end color #1f
Andreas93 [3]

Answer:

  1. Area of the rectangle: 24 cm²
  2. Area of the circle: 380.13 cm²
  3. Area of between the circle and the rectangle: 356.13 cm²

Explanation:

The question describes<em> a rectangle of dimensions  4 cm × 6 cm inscribed in a circle with radius 11 cm</em>.

You can find:

  • The area of the rectangle
  • The area of the circle
  • The area between the rectangle and the circle.

<u>1. Area of the rectangle:</u>

Area=length\times width=4cm\times 6cm=24cm^2

<u>2. Area of the circle:</u>

Area=\pi\times radius^2=\pi \times (11cm)^2\approx 380.13cm^2

<u>3. Area between the rectangle of the circle:</u>

This is the area of the circle that does not belong to (or is outside of) the area of the rectangle.

Area=\text{area of the circle - area of the rectangle}\\ \\ Area=380.13cm^2-24cm^2=356.13cm^2

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3 years ago
Read 2 more answers
Tim has to cover 3 tanks completley with paint. ​
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<em>answer:</em>

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<em>Solution</em><em>,</em>

<em>diameter </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>4</em><em> </em><em>m</em>

<em>Height </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>Given </em><em>tank </em><em>has </em><em>top </em><em>and </em><em>bottom </em>

<em>Now,</em><em> </em><em>The </em><em>total </em><em>surface </em><em>area </em><em>of </em><em>cylinder </em><em>tank </em><em>is </em><em>given </em><em>by:</em>

<em>tsa = 2\pi \:  {r}^{2}  + (2\pi \: r \: ) \times h</em>

<em>r(</em><em> </em><em>radius </em><em>of </em><em>tank)</em><em>=</em>

<em>\frac{diameter}{2}  =  \frac{1.4}{2}  = 0.7 \: m</em>

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<em>TSA </em><em>of </em><em>1</em><em> </em><em>tank</em>

<em>=</em>

<em>2 \times 3.14 \times  {(0.7)}^{2}  + 2 \times 3.14 \times 0.7 \times 1.9 \\  = 11.435 \:  {m}^{2}</em>

<em>TSA </em><em>Of </em><em>3</em><em> </em><em>tanks</em>

<em>=</em>

<em>3 \times 11.435 \:  {m}^{2}  \\  = 34.3 \:  {m}^{2}</em>

<em>Given </em><em>a </em><em>tin </em><em>of </em><em>plate </em><em>covers </em><em>5</em><em>m</em><em>^</em><em>2</em><em> </em><em>area.</em>

<em>No.of </em><em>tins </em><em>required:</em>

<em>1</em><em> </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>5</em><em>m</em><em>^</em><em>2</em>

<em>x </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em>

<em>5x = 34.3(cross \: multiplication) \\ or \: x =  \frac{34.3}{5}  \\ x = 6.86 \\ x = 7 \: tins</em>

<em>there</em><em>fore</em><em> </em><em>7</em><em> </em><em>tins </em><em>are </em><em>required</em><em>.</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>

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Answer:

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Step-by-step explanation:

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Of the two variables one variable is dependent upon the other.

Dependent variables are those variables that are under study, i.e. they are being observed for any changes when the other variable values are changed.

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With every sphere that Grissom draws, the volume of the sphere changes according to its diameter length.

That is the volume of the sphere depends upon the length of its diameter.

Thus, the independent quantity in the situation is the length of the diameter.

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