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iris [78.8K]
2 years ago
5

The ________ is the agreed-upon interface between all the software that runs on the machine and the hardware that executes it. I

t allows you to talk to the machine.
Computers and Technology
1 answer:
Talja [164]2 years ago
4 0

Answer:

The correct answer to the following question will be "Instruction set architecture".

Explanation:

The Instruction Series Design is a component of the system that is accessible to the compiler and the programmer. It is also the distinction between hardware and software. We will describe in detail the set of instructions used in most of the microprocessors that are used today.

The processor ISA can be represented using 5 categories, these are as follows:

  • The RAM Running Memory.
  • Amount of clear operating names.
  • Location of operands.
  • Operations
  • Size and type of the operand.

Therefore, Instruction set architecture is the right answer.

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What is a lan adapter
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Answer:

A LAN adapter is an expansion board that is used to connect a computer or computing device to a network. LAN adapter is the most common and generic alternate name for a Network Interface Card (NIC).

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Half of the integers stored in the array data are positive, and half are negative. Determine the
jonny [76]

Answer:

Check the explanation

Explanation:

Below is the approx assembly code for above `for loop` :-

1). mov ecx, 0

2). loop_start :

3).    cmp ecx, ARRAY_LENGTH

4).    jge loop_end

5).    mv temp_a, array[ecx]

6).    cmp temp_a, 0

7).    branch on nge

8).        mv array[ecx], temp_a*2

9).   add ecx, 1

10).   jmp loop_start

11). loop_end :

Assumptions :-

*ARRAY_LENGTH is register with value 1000000

*temp_a is a register

Frequency of statements :-

1) will be executed one time

3) will be executed 1000000 times

4) will be executed 1000000 times

5) will be executed 1000000 times

6) will be executed 1000000 times

7) `nge` will be executed 1000000 times, branch will be executed 500000 times

8) will be executed 500000 times

9) will be executed 1000000 times

10) will be executed 1000000 times

Cost of statements :-

1) 10 ns

3) 10ns + 10ns + 10ns [for two register accesses and one cmp]

4) 10ns [for jge ]

5) 10ns + 100ns + 10ns [10ns for register access `ecx`, 100ns for memory access `array[ecx]`, 10ns for mv]

6) 10ns + 10ns [10ns for register_access `temp_a`, 10ns for mv]

7) 10ns for nge, 10ns for branch

8) 30ns + 110ns + 10ns

10ns + 10ns + 10ns for temp_a*2 [10ns for moving 2 into a register, 10ns for multiplication],

110ns for array[ecx],

10ns for mv

9) 10ns for add, 10ns for `ecx` register access

10) 10ns for jmp

Total time taken = sum of (frequency x cost) of all the statements

1) 10*1

3) 30 * 1000000

4) 10 * 1000000

5) 120 * 1000000

6) 20 * 1000000

7) (10 * 500000) + (10 * 1000000)

8) 150 * 500000

9) 20 * 1000000

10) 10 * 1000000

Sum up all the above costs, you will get the answer.

It will equate to 0.175 seconds

7 0
2 years ago
Using the find and replace tool would be most appropriate when
mafiozo [28]

A. Changing the company name when the same letter is sent to different companies

The find and replace tool is meant to help replace all instances of a certain piece of text with a different piece of text.

For example, if a letter was sent to Company A, the find and replace tool could change every time the letter says “Company A” and make it say “Company B” instead so the same letter could be sent to Company B.

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