. Let F(X, Y, Z)=(X + Y + Z)(X + Y + Z)(X + Y + Z)(X + Y + Z). Use a 3-variable K-Map to find the minimized SOP form of this fun
ction. Hint: When you go to fill in the K-Map, you may have trouble figuring out where to put the 0s and 1s because F is specified in POS form. Your first impulse may be to try to multiply out these terms to convert it into SOP form, and then use that to fill in the K-Map. This would be logically correct but a ton of work. Instead you can use the POS form to determine where to place the 0s in the K-Map. For example, the first term (X+Y +Z) implies that you should put a zero in the square that corresponds to (X + Y + Z¯). Now use DeMorgan’s to see that (X + Y + Z¯) = X ·Y ·Z and place a 0 in the corresponding square. Repeat this for all the product terms; then you can fill in 1s in the squares without 0s.
1 answer:
Answer:
Kindly see explaination
Explanation:
The k-map van be defined as a map that provides a pictorial method of grouping together expressions with common factors and therefore eliminating unwanted variables. The Karnaugh map can also be described as a special arrangement of a truth table.
Please kindly check attachment for the 3-variable K-Map to find the minimized SOP form of the function in the question.
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Answer:
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Let s represent the slant height;
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The slant height, s is calculated using Pythagoras theorem as thus
The perimeter of the triangle is then calculated as thus;
For the volume of the cone,
when the triangle is spin, the base of the triangle forms the diameter of the cone;
Where
So,
So,
Base on the above illustrations, the program is as follows;
#include<iostream>
#include<cmath>
using namespace std;
void CalcArea(double b, double h)
{
//Calculate Area
double Area = 0.5 * b * h;
//Print Area
cout<<"Area = "<<Area<<endl;
}
void CalcPerimeter(double b, double h)
{
//Calculate Perimeter
double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;
//Print Perimeter
cout<<"Perimeter = "<<Perimeter<<endl;
}
void CalcVolume(double b, double h)
{
//Calculate Volume
double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;
//Print Volume
cout<<"Volume = "<<Volume<<endl;
}
int main()
{
double b, h;
//Prompt User for input
cout<<"Base: ";
cin>>b;
cout<<"Height: ";
cin>>h;
//Call CalcVolume function
CalcVolume(b,h);
//Call CalcArea function
CalcArea(b,h);
//Call CalcPerimeter function
CalcPerimeter(b,h);
return 0;
}