9x8y12 it a lot of work to do so I don't want to type how to do the problem
Hahahahahhahahahahahhahhahahahahhahahahhahahahahahahhahahahahhahahahahahahahhahahahhahahahahhahahhahahahhahhahahhabbabaabbahahhahahahabahahhaabbahahahhahhababhahahhahabhahahhahahha thanks for the points !!!!!!
The initial value is 3 (when x=0), and the multiplier is 2, when x=2. The equation can be written as
.. y = 3*(2^(x/2))
We are to form the combination of 6 objects taken 2 at a time. This can be expressed as 6C2

This means, there can be 15 different combinations of 2 members that can sit in the front row.
So, the answer to this question is option A