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djverab [1.8K]
2 years ago
7

A swimsuit discount 65% on sale for $20.30. what is the original price and how

Mathematics
1 answer:
stepladder [879]2 years ago
4 0
20.30x(1+65%)
=20.3x1.65
=33.495
Because is the money, so the answer should be $33.50.
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Question 7 of 12<br> 64 =<br> O A. 9<br> OB. 7<br> C. 8<br> O D. 16<br> Pleaseee
sasho [114]

Answer:7

Step-by-step explanation:

7 0
3 years ago
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An enterprise rents out paddle boats for all-day use on a lake. The owner knows that he can rent out all 40 of his paddleboats i
PSYCHO15rus [73]

Answer:

<u>The owner's total revenue would be</u><u> $204</u><u> if he charged $6 for each paddle boat rental.</u>

Step-by-step explanation:

The owner has a total of 40 paddle boats and he can rent out all of them if he charges $3 per paddle boat. For each extra dollar, the number of paddle boats will decrease by 2. So, if he charges $6 (3 extra dollars) for each rental he can rent out:

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The total revenue can be calculated by multiplying the number of paddle boats rented by the rent price per paddle boat.

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<u>The owner's total revenue would be</u><u> $204</u><u> if he charged $6 for each paddle boat rental.</u>

4 0
2 years ago
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HELP PLEASE! if a||b what is the value of x?
Norma-Jean [14]

Answer: x=30 (Sorry for wasting your time if the answer is wrong)


Step-by-step explanation:

I did it the lazy way

80-20=60

60÷2=30

(If this is completely wrong then again, sorry)

8 0
3 years ago
Jared bought a Suzuki 1000 for $12,698. If it depreciates at a rate of 11% per year, how much will it be worth in 3 years
Serga [27]
Original price = P = $12,698
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The formula used will be:

A=P(1-r)^{t}

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7 0
2 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

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For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

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⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
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