What is the average rate of change of the function over the interval x = 0 to x = 8? f(x)=2x−1/3x+5 Enter your answer, as a frac

Question

3 years ago

9

tion, in the box.

1 answer:

max2010maxim [7] · Answer 1 · 2022-05-22T14:30:10+03:00

Answer:

15 2/3, or 47/3

Step-by-step explanation:

I'm going to assume, correctly or not, that you actually meant f(x) = 2x^2 - (1/3)x + 5. Double check on this right now, please.

If I'm right, then evaluate f(x) at x = 0 and x = 8:

f(0) = 5

and

f(8) = 2(8)^2 - (1/3)(8) + 5 = 128 - 8/3 + 5 = 133 - (2 2/3), or: 130 1/3

Then the average rate of change of f(x) = 2x^2 - (1/3)x + 5 over the interval [0,8] is:

130 1/3 - 5 125 1/3

a. r. c. = ------------------- = ---------------- = 15 2/3, or 47/3

8 - 0 8