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polet [3.4K]
3 years ago
8

Nzkmaldfoasdgfjsadof

Mathematics
1 answer:
lidiya [134]3 years ago
7 0

Answer:

hiiiiiiiiiiiiiiiiiiiiiiii

Step-by-step explanation:

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Help. Look at image. I don't get this.
Nadusha1986 [10]

Answer:

she spent 91.18 dollrs

Step-by-step explanation:

simply add the blouse shoes and shirt prices,

times .20, subtract frmo total

6 0
3 years ago
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45 plants cost<br>Rs 180<br>find cost of 65 Plant​
lesya692 [45]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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Two payment options to rent a car: You can pay $20 a day plus 25¢ a mile (Option A) or pay $10 a day plus 50¢ a mile (Option B).
BaLLatris [955]

You must drive more than 40 miles to make option A the cheaper plan

<em><u>Solution:</u></em>

Two payment options to rent a car

Let "x" be the number of miles driven in one day

<em><u>You can pay $20 a day plus 25¢ a mile (Option A)</u></em>

25 cents is equal to 0.25 dollars

OPTION A :  20 + 0.25x

<em><u>You pay $10 a day plus 50¢ a mile (Option B)</u></em>

50 cents equal to 0.50 dollars

Option B: 10 + 0.50x

<em><u>For what amount of daily miles will option A be the cheaper plan ?</u></em>

For option A to be cheaper, Option A must be less than option B

Option A < Option B

20 + 0.25x < 10 + 0.50x

Solve the inequality

Add -0.50x on both sides

20 +0.25x -0.50x < 10 + 0.50x - 0.50x\\\\20 - 0.25x < 10

Add - 20 on both sides,

20 - 0.25x - 20 < 10 - 20\\\\-0.25x < -10

\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}

0.25x > 10

Divide both sides by 0.25

x > 40

Thus you must drive more than 40 miles to make option A the cheaper plan

7 0
3 years ago
12. Rileigh plays softball. She has 12 softball
Lelechka [254]

Answer:

3:10

Step-by-step explanation:

i did it on paper and took a test on ratios a while ago and i got this answer have a good day and i hope you get a 100 :)

8 0
2 years ago
If the vertex of a parabola is (-4, 6) and another point on the curve is (-3, 14), what is the coefficient of the squared expres
Luda [366]
\bf \qquad \textit{parabola vertex form}\\\\\begin{array}{llll}&#10;\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\&#10;x=a(y-{{ k}})^2+{{ h}}&#10;\end{array}\qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\&#10;-------------------------------\\\\&#10;vertex\ (-4,6)\qquad &#10;\begin{cases}&#10;h=-4\\&#10;k=6&#10;\end{cases}\implies y=a(x-(-4))^2+6&#10;\\\\\\&#10;y=a(x+4)^2+6&#10;\\\\\\&#10;\textit{we also know that }&#10;\begin{cases}&#10;x=-3\\&#10;y=14&#10;\end{cases}\implies 14=a(-3+4)^2+6

solve for "a"
8 0
3 years ago
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