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notka56 [123]
3 years ago
15

Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on

e chip has the number 3, and the other chip has the number 5. Miguel must choose two chips, and if both chips have the same number, he wins $2. If the two chips he chooses have different numbers, he loses $1 (–$1).
Let X = the amount of money Miguel will receive or owe. Fill out the missing values in the table. (Hint: The total possible outcomes are six because there are four chips and you are choosing two of them.)





Xi

2

–1

P(xi)









What is Miguel’s expected value from playing the game?









Based on the expected value in the previous step, how much money should Miguel expect to win or lose each time he plays?







What value should be assigned to choosing two chips with the number 1 to make the game fair? Explain your answer using a complete sentence and/or an equation.
Mathematics
2 answers:
boyakko [2]3 years ago
7 0

Answer:

idk what exactly this is asking buut here is my best answer

Step-by-step explanation:

1+1=2(3+5=-1)

since 6 is the possible outcoe .idk what its exacly askign so if u can help with tht that wuld be grest .

Need 1 more brainliest

 

Shalnov [3]3 years ago
3 0

Answer:

To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.

The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)

We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.

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5 0
2 years ago
What is the area of the shaded region?
kolezko [41]

Answer:

110 cm^2

Step-by-step explanation:

The first thing that you need to do is find the area of triangle AFE. The area of a triangle is always base*height/2. So in this case, that would be 10*6 divided by 2, which is 30 cm. Next, you will need to know the area of triangle ECB. Using that same formula, you will get 8*10/2, which is 40 cm. Finally, you will need to find the area of the whole rectangle. The area of a rectangle is always the length times the width. In this case, you would have 10*18, which is 180 cm. To get your final answer, you need to subtract the areas of the unshaded area from the whole area. That would be 180-(30+40), which is 110 cm. I hope this helped!

6 0
2 years ago
The sum of a whole number and twice its square is 21. Find the whole number
I am Lyosha [343]
SOLUTION:

Let whole number = x

x + 2x^2 = 21

2x^2 + x - 21 = 0

2x^2 + 7x - 6x - 21 = 0

x ( 2x + 7 ) - 3 ( 2x + 7 ) = 0

( 2x + 7 ) ( x - 3 ) = 0


2x + 7 = 0

2x = - 7

x = - 7 / 2

OR

x - 3 = 0

x = 3


ANSWER:

Therefore, as 3 is a whole number while - 7 / 2 isn't a whole number, the whole number must be 3.

Hope this helps! :)
Have a lovely day! <3
6 0
3 years ago
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