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2 years ago

9

Jenny has a new box of 8 colored pencils. Each one is perfectly sharpened. Together the colored pencils have a mass of 56 grams

1 answer:

storchak [24]2 years ago

8 0

Answer:

If you are trying to find how much grams are in one color pencil it is 7 grams.

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Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

<u>Applying formula (1):</u>

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

<u>Applying formula (2):</u>

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

2 years ago

Which statement about the sum of the interior angle measures of a triangle in Euclidean and non Euclidean geometries are true

Sati [7]

Where are the statements?

7 0

3 years ago

Read 2 more answers

.12÷.6492 is what answer

White raven [17]

Answer:

.000018484

Step-by-step explanation:

You divide them and that is what your calculator says

4 0

3 years ago

Read 2 more answers

Find the value of each value

amid [387]

W+2=3
w=3-2
so the answer is w=1

7 0

2 years ago

Absolute value inequalities. 10-4|9y-10|<-94

Ivahew [28]

Answer: $\begin{bmatrix}\mathrm{Solution:}\:&\:y4\:\\ \:\mathrm{Decimal:}&\:y4\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:-\frac{16}{9}\right)\cup \left(4,\:\infty \:\right)\end{bmatrix}$

Step-by-step explanation:

$10-4\left|9y-10\right|$

$10-4\left|9y-10\right|-10$

$-4\left|9y-10\right|$

$\left(-4\left|9y-10\right|\right)\left(-1\right)>\left(-104\right)\left(-1\right)$

$4\left|9y-10\right|>104$

$\frac{4\left|9y-10\right|}{4}>\frac{104}{4}$

$\left|9y-10\right|>26$

$9y-1026$

$y4$

5 0

2 years ago