Question

E2%7D%20" id="TexFormula1" title=" \frac{3}{2n} + \frac{1}{n^2} = \frac{n-2}{2n^2} " alt=" \frac{3}{2n} + \frac{1}{n^2} = \frac{n-2}{2n^2} " align="absmiddle" class="latex-formula">

Answer 1

Make denomenators the same
common denom is 2n²

multiply 3/2n by n/n
mulitply 1/n² by 2/2

we get
$\frac{3n}{2n^2}+\frac{2}{2n^2}=\frac{n-2}{2n^2}$
combine fractions
$\frac{3n+2}{2n^2}=\frac{n-2}{2n^2}$
multiply both sides by 2n²
2n+2=n-2
minus n both sides
n+2=-2
minus 2 both sides
n=-4