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Aleonysh [2.5K]
3 years ago
15

Find the length of BC.

Mathematics
2 answers:
Phantasy [73]3 years ago
6 0
If AB is 6 and AC is 4. Look at how BC it longer than AC but shorter than AB. The number in between would be 5 so the answer is 5cm.
morpeh [17]3 years ago
3 0
It could be 5 I think
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In the number 432.785 which number is the hundredths digit
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The number in the hundredths digit is 8.
7 0
3 years ago
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I need help!!!
Kruka [31]

Answer: x = -3/4 can not be a rational zero of the polynomial.

Step-by-step explanation:

We have the polynomial:

6x^5 + ax^3 -bx -12 = 0.

The theorem says that:

If P(x) is a polynomial with integer coefficients, and p/q is a zero of P(x) then p is a factor of the constant term (in this case the constant term is -12) and q is a factor of the leading coefficient (in this case the leading coefficient is 6.).

The factors of -12  (different than itself) are (independent of the sign).

1, 2, 3, 4 and 6.

So p can be: 1, -1, 2, -2, 3, -3, 4, -4, 6, -6.

The factors of 6 are:

1, 2 and 3, so q can be 1, -1, 2, -2, 3, -3.

Then the option that can not be a zero of the polynomial is

x = -3/4

because the number in the denominator must be a factor of the leading coefficient, and 4 is not a factor of six.

4 0
4 years ago
gina writes 2 pages per hour write an equation that shows the relationship between the hours spent writing x and the total pages
mart [117]

Answer:

y=2x

Step-by-step explanation:

6 0
3 years ago
A window box in the shape of a rectangular prism is 7 inches long and 4 inches wide. It holds 168 cubic inches of dirt. What is
Pepsi [2]

Answer:

6 inches

Step-by-step explanation:

The formula for volume is length*width*height. Following this,

7*4*h=168

28h=168

h=6

5 0
3 years ago
Read 2 more answers
If the vertex of a parabola is (-4, 6) and another point on the curve is (-3, 14), what is the coefficient of the squared expres
Luda [366]
\bf \qquad \textit{parabola vertex form}\\\\\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array}\qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex\ (-4,6)\qquad 
\begin{cases}
h=-4\\
k=6
\end{cases}\implies y=a(x-(-4))^2+6
\\\\\\
y=a(x+4)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=-3\\
y=14
\end{cases}\implies 14=a(-3+4)^2+6

solve for "a"
8 0
4 years ago
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