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netineya [11]
3 years ago
5

If the vertex of a parabola is (-4, 6) and another point on the curve is (-3, 14), what is the coefficient of the squared expres

sion in the parabola's equation?
Mathematics
1 answer:
Luda [366]3 years ago
8 0
\bf \qquad \textit{parabola vertex form}\\\\\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array}\qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex\ (-4,6)\qquad 
\begin{cases}
h=-4\\
k=6
\end{cases}\implies y=a(x-(-4))^2+6
\\\\\\
y=a(x+4)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=-3\\
y=14
\end{cases}\implies 14=a(-3+4)^2+6

solve for "a"
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3 years ago
CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION
Murljashka [212]

Answer:

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Step-by-step explanation:

The triangles ABC and DCA are right angled triangles.

The straight line AC is a bisector for angles C and A.

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Then the measure of angles BCA and ACD will be 15° each.

The measure of angle DAB is 150°.

Then the measure of angles DAC and BAC will be 75° each.

Now consider the right angled triangle ABC.

The measure of side AC is:

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Consider the right angled triangle DCA.

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Using the trigonometric identities compute the value of Perpendicular DC as follows:

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7 0
3 years ago
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Readme [11.4K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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