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fredd [130]
3 years ago
7

c=1 when a randomly chosen card out of a standard deck of 52 playing cards is a heart and c=2 otherwise. draw a histogram showin

g probibility distribution for the random variable ​

Mathematics
1 answer:
Lilit [14]3 years ago
8 0

Answer:

The possible values of c are 1 or 2. There are 13 hearts in a deck of cards and 52-13 = 39 cards that are not. There are a total of 52 cards to choose from, so the possibilities for each value of c are found by dividing the number of results for that value by 52. (Image 1)

Histogram is attached for your reference.

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3(x-1) - 8 = 4(1+x) +5. Too hard, i keep getting confused
svet-max [94.6K]

3(x-1)-8=4(1+x)+5  

One solution was found :

                  x = -20

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    3*(x-1)-8-(4*(1+x)+5)=0  

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 ((3•(x-1))-8)-(4•(x+1)+5)  = 0  

Step  2  :

Equation at the end of step  2  :

 (3 • (x - 1) -  8) -  (4x + 9)  = 0  

Step  3  :

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

  -x - 20  =   -1 • (x + 20)  

Equation at the end of step  4  :

 -x - 20  = 0  

Step  5  :

Solving a Single Variable Equation :

5.1      Solve  :    -x-20 = 0  

Add  20  to both sides of the equation :  

                     -x = 20

Multiply both sides of the equation by (-1) :  x = -20

One solution was found :

                  x = -20

hope this is wht u wanted

4 0
3 years ago
What is a/b if a-b=2
ad-work [718]

Answer:

Step-by-step explanation:

2+b/ b pretend this is a fraction

6 0
3 years ago
Which quadratic function in vertex form can be represented by the graph that has a vertex at (3, -7) and passes through the poin
yarga [219]

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=3\\ k=-7 \end{cases}\implies y=a(x-3)^2-7\qquad \textit{we also know that} \begin{cases} x=1\\ y=-10 \end{cases} \\\\\\ -10=a(1-3)^2-7\implies -3=a(-2)^2\implies -3=4a\implies -\cfrac{3}{4}=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-\cfrac{3}{4}(x-3)^2-7~\hfill

5 0
1 year ago
PLEASE HELP, GIVING 55 POINTS IF YOU ANSWER (08.03/08.05 MC) A pair of equations is shown below: y = 3x − 5 y = 6x − 8 Part A: E
Andrew [12]

Answer:

  A. (1, -2)

  B. the lines intersect at the solution point: (1, -2).

Step-by-step explanation:

A. The equations can be solve by substitution by using the y-expression provided by one of them to substitute for y in the other.

This gives ...

  3x -5 = 6x -8

Adding 8-3x to both sides, we get ...

  3 = 3x

Dividing both sides by 3 gives ...

  1 = x

Substituting this value into the first equation, we can find y:

  y = 3(1) -5 = -2

The solution is (x, y) = (1, -2).

__

B. The lines intersect at the solution point, the point that satisfies both equations simultaneously. That point is (1, -2).

8 0
3 years ago
-5: -2; 1;<br><br>write the next 3 terms​
Nataly_w [17]

Answer:

Next 3 of the sequence are 4, 7, 10

You are adding by 3.

-2 - -5= 3

-2 + 3=1

1+3=4

4+3=7

7+3=10

5 0
2 years ago
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