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castortr0y [4]
2 years ago
8

A random sample of size 16 is to be taken from a normal population having mean of 100 andvariance 4. What is the 90th percentile

of the distribution of x?
Mathematics
1 answer:
viva [34]2 years ago
3 0

Answer:  100+1.28(1/2)=100.64

Step-by-step explanation:

A random sample of size 16 is to be taken from a normal population having mean 100 and variance 4. ... The 90th percentile of the normal curve, according to the table I was provided, was equal to 1.28 standard units above the mean.

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Write the formula for finding the volume of a prism
solniwko [45]
Base area* height

base area:
parallelogram: width*length
triangles: (height * base) /2
5 0
3 years ago
Need help only on odds please
mars1129 [50]

Answer:

Step-by-step explanation:

1) (i) HG ≅ ST ;      GI ≅ TR ;           IH ≅ RS

ΔHGI ≅ ΔSTR     by  S S S congruent

(ii) ∠H ≅ ∠S      ;  HG ≅ ST       ; ∠G ≅ ∠T

ΔHGI ≅ ΔSTR     by A S A -> Angle Side Angle congruent.

3) LM ≅ XY ;          MK ≅ YZ  ;      KL ≅ ZX

ΔLMK ≅ ΔXYZ Side Side Side congruent

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8 0
2 years ago
I need help asap I'll give brainliest
weqwewe [10]

What's the question?

5 0
3 years ago
What is 30=-5(6n+6) im confused
Flauer [41]

Answer:

Step-by-step explanation:

30 = -5(6n + 6)...distribute the 5 thru the parenthesis

30 = -30n - 30....add 30 to both sides

30 + 30 = -30n

60 = -30n....divide both sides by -30

-60/30 = n

-2 = n <===

5 0
3 years ago
Please help me !!!!!!!!!!!!!!!!
Nutka1998 [239]

Answer: x=-10, y=13

Step-by-step explanation:

-3x+2y=56\\-5x-2y=24

+2y-2y = 0, eliminating y is much easier. So -3x-5x = -8x and 56+24 = 80

-8x=80\\x=-10

Substitute x in any equations but only 1 equation (Don't substitute in both equations.)

For me, I'd substitute x in -3x+2y=50

-3(-10)+2y=56\\30+2y=56\\2y=56-30\\2y=26\\y=13

So the answer is x = -10, y = 13

5 0
3 years ago
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