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Ad libitum [116K]
3 years ago
11

I don’t get it which one is it

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0
The area of a parallelogram is base * hight.

Choice A: base = 10 & hight = 12,
so area = 10*12 = 120

Choice B: base = 10 & hight = 6,
so Area = 10*6 = 60

To practice, try to find the area for choice c & d.
If your still having trouble, search Google for "how to find area of a parallelogram".
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Assume a fair deck of playing cards. Find the probability of drawing a 10, replacing it and drawing an ace.
cupoosta [38]

Answer:

There are 52 cards in a deck. The total number of outcomes possible when picking 2 cards and replacing them is 52 * 52 = 2704.

There are 4 10s and 4 aces so the total number of successful outcomes = 4 * 4 = 16.

Probability = 16 / 2704 = 1 / 169

6 0
3 years ago
What percentage is $7,360 of $78,000
Svet_ta [14]
I'd say 7.360 / 78.000 * 100 = 9,4359 % 
7 0
4 years ago
Read 2 more answers
Factor the following (in picture)
sertanlavr [38]

Step-by-step explanation:

<em>I </em><em>hope</em><em> this</em><em> will</em><em> help</em><em> you</em>

7 0
2 years ago
Without actual division prove that x4 +2x3 -2x2 +2x -3 is exactly divisible by<br> x2 +2x-3
Brut [27]

Answer:

Step-by-step explanation:                

\displaystyle\Large\boldsymbol{} x^4+2x^3-2x^2+2x-3= \\\\\\x^4+2x^2(x-1)+2x-\underbrace{2-1}_{-3}=  \\\\\\x^4-1+2x^2(x-1)+2x-2 = \\\\\\(x^2-1)(x^2+1)+2x^2(x-1)+2(x-1) = \\\\\\\underline{(x-1)}(x+1)(x^2+1)+2x^2\underline{(x-1)} +2\underline{(x-1)} =\\\\\\(x-1)((x+1)(x^2+1)+2x^2+2)=\\\\\\(x-1)(x^3+x^2+2x^2+x+2+1)=\\\\\\(x-1)(x^3+3x^2+x+3) =\\\\\\(x-1)( \underline{(x+3)}x^2+\underline{(x+3)})=(x^2+1)\underbrace{(x-1)(x+3)}_{x^2+2x-3}= \\\\\\(x^2+1)(x^2+2x-3) : (x^2+2x-3)=x^2+1

7 0
3 years ago
The bacterial strain Acinetobacter has been tested for its adhesion properties, which is believed to follow a normal distributio
pantera1 [17]

Answer:

a) Alternative hypothesis should be one sided. Because Null and Alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b) the hypothesis that mean adhesion is at least 2.66 dyne-cm is true

Step-by-step explanation:

Let μ be the mean adhesion in dyne-cm.

a)

Null and alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b)

First we need to calculate test statistic and then the p-value of it.

test statistic of sample mean can be calculated as follows:

t=\frac{X-M}{\frac{s}{\sqrt{N} } } where

  • X  is the sample mean
  • M is the mean adhesion assumed under null hypothesis (2.66 dyne-cm)
  • s is the standard deviation known  (0.7 dyne-cm_2)
  • N is the sample size(5)

Sample mean is the average of 2.69, 5.76, 2.67, 1.62 and 4.12 dyne-cm, that is \frac{2.69+5.76+2.67+1.62+4.12}{5} ≈ 3.37

using the numbers we get

t=\frac{3.37-2.66}{\frac{0.7}{\sqrt{5} } } ≈ 2.27

The p-value is ≈ 0.043. Taking significance level as 0.05, we can conlude that sample proportion is significantly higher than 2.66 dyne-cm.

Thus, according to the sample the hypothesis that mean adhesion is at least 2.66  dyne-cm is true

3 0
3 years ago
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