Answer:
8/x+2 or ![\frac{8}{2+x}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B2%2Bx%7D)
Step-by-step explanation:
To answer, carefully read the question and pick up on key words like "sum." To begin, we know that "sum" means addition, therefore the sum of 2 and a number (which will be replaced by the variable x) is equivilent to 2 + x. Furthermore, we know that 8 is being divided by the sum. So, the final expression should be
. Good luck!
When multiplying you add powers. So it would be 18x^8
Answer:
ggabdfsa
Step-by-step explanation:
When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.
For example:
![(x^4)^3=x^{(4*3)}=x^{12}](https://tex.z-dn.net/?f=%28x%5E4%29%5E3%3Dx%5E%7B%284%2A3%29%7D%3Dx%5E%7B12%7D)
![(2^1)^3=2^{(1*3)}=2^3=8](https://tex.z-dn.net/?f=%282%5E1%29%5E3%3D2%5E%7B%281%2A3%29%7D%3D2%5E3%3D8)
Your answer is 5^(12)
Answer:
![q=2](https://tex.z-dn.net/?f=q%3D2)
Step-by-step explanation:
We need to find the quantity demanded if the price of the shed is 1480$. Hence:
![D(q)=1480=-4q^{2}-2q+1500](https://tex.z-dn.net/?f=D%28q%29%3D1480%3D-4q%5E%7B2%7D-2q%2B1500)
Sustract 1480 to both sides:
![-4q^{2} -2q+20=0](https://tex.z-dn.net/?f=-4q%5E%7B2%7D%20-2q%2B20%3D0)
Multiply both sides by ![\frac{-1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B4%7D)
![q^{2}+\frac{1}{2}q-5=0](https://tex.z-dn.net/?f=q%5E%7B2%7D%2B%5Cfrac%7B1%7D%7B2%7Dq-5%3D0)
We have a quadratic equation, we can solve it using the cuadratic formula or simply factoring it:
![(q+\frac{5}{2})(q-2)](https://tex.z-dn.net/?f=%28q%2B%5Cfrac%7B5%7D%7B2%7D%29%28q-2%29)
Now the solutions are given by:
![q_1=-\frac{5}{2} \\q_2=2](https://tex.z-dn.net/?f=q_1%3D-%5Cfrac%7B5%7D%7B2%7D%20%5C%5Cq_2%3D2)
Since we look for a coherent answer we take the positive solution ![q_2](https://tex.z-dn.net/?f=q_2)
So the quantity demanded is ![q=2](https://tex.z-dn.net/?f=q%3D2)