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KiRa [710]
3 years ago
7

Solve the system of linear equations by substitution

Mathematics
1 answer:
marin [14]3 years ago
7 0
Im sorry i would help but i cant read the paper 

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A) 10<br> b) 12<br> c) 8 <br> d) 6
Nostrana [21]
B or c sorry if I’m wrong tho :(
8 0
3 years ago
Read 2 more answers
Use technology or a z-score table to answer the question.
AlexFokin [52]

Answer:

D. 100

Step-by-step explanation:

1. Find the z-score: 165-176/11.4 = -1.2

2. Find the percentage of the z-score. Here it's 16.85%

3. Because we are searching for the amount of members that weigh MORE than 165 pounds and not LESS, we need to find the greater percentage by subtracting 16.85% from 100% which is 83.15%. This is the percentage of people that weigh more than 165 pounds.

4. Multiply the percentage by the number of members: 83.15%*120 = 99.78

5. Round it to a whole number because someone can't be 0.78 of a person. You get 100 members.

Also, I took the test :)

7 0
3 years ago
Can you please factor x^2-2x-31?
algol [13]
Multiply the coefficient of the first term by the constant 1 • -31 = -31

Find two factors of -31 whose sum equals the coefficient of the middle term, which is -2 .

-31 + 1 = -30
-1 + 31 = 30

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
8 0
3 years ago
A parabolà can be drawn given a focus of (7,9) and a
NeTakaya

from the provided focus point and directrix, we can see that the focus point is above the directrix, meaning is a vertical parabola and is opening upwards, thus the squared variable will be the "x".

keeping in mind the vertex is half-way between these two fellows, Check the picture below.

\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\bf \begin{cases} h = 7\\ k = 7\\ p = 2 \end{cases}\implies 4(2)(y-7)=(x-7)^2\implies 8(y-7)=(x-7)^2 \\\\\\ y-7=\cfrac{1}{8}(x-7)^2\implies \boxed{y=\cfrac{1}{8}(x-7)^2+7}

6 0
4 years ago
Which one is it?? <br> (btw the negative answer isn't right.)
Semmy [17]

Answer:

A

Step-by-step explanation:

Rule: a Minus power always goes to the opposite place to where it is. If it is in the denominator, it goes to the numerator. If it is the numerator, it goes to the denominator. The minus power does not affect the sign of the expression.

So you are right. The minus power does not give a minus answer.

\dfrac{y^{-2}}{3y^4}=\dfrac{1}{3y^2y^4}=\dfrac{1}{3y^{(2 + 4)}} = \dfrac{1}{3y^6}

Answer: A


4 0
4 years ago
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