36p Should be your answer
Answer: 12.56 feet
Step-by-step explanation:
Given: The width of the circular path= 2 feet
The inner diameter of circular path= 150 feet
Therefore, the inner radius of circular path=![\frac{150}{2}=75\ ft](https://tex.z-dn.net/?f=%5Cfrac%7B150%7D%7B2%7D%3D75%5C%20ft)
Now, the outer radius= 75+2=77 feet
We know that the circumference= ![2\pi r](https://tex.z-dn.net/?f=2%5Cpi%20r)
Inner circumference= ![2\pi 75=150\pi](https://tex.z-dn.net/?f=2%5Cpi%2075%3D150%5Cpi)
Outer circumference= ![2\pi 77=154\pi](https://tex.z-dn.net/?f=2%5Cpi%2077%3D154%5Cpi)
The difference= ![154\pi-150\pi=4\pi=4\times3.14=12.56\ feet](https://tex.z-dn.net/?f=154%5Cpi-150%5Cpi%3D4%5Cpi%3D4%5Ctimes3.14%3D12.56%5C%20feet)
Hence, the outer edge of the path is 12.56 feet farther than the inner edge
See attached file for the drawing and illustration of the given problem.
I have assigned "X" to be the length of the ramp.
We can use and apply SOH CAH TOA to find the value of x. The solution is shown below:
sin4.5 ° = 3 / x
x = 3/sin4.5
x= 38.2°
The answer is the letter "D".
Answer:
w=5
Step-by-step explanation:
two negatives is a positive
You would save $2.99
Work: 14.99 / 5 = 2.99