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34kurt
3 years ago
12

How do i solve x/3+10=15

Mathematics
1 answer:
yaroslaw [1]3 years ago
8 0

step-by-step.

x

3

+10=15

Step 1: Simplify both sides of the equation.

1

3

x+10=15

Step 2: Subtract 10 from both sides.

1

3

x+10−10=15−10

1

3

x=5

Step 3: Multiply both sides by 3.

3*(

1

3

x)=(3)*(5)

x=15

Answer:

x=15

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Answer:

The zeros are 6,-5,9

Step-by-step explanation:

The factored form of the polynomial is given as:

f(x) = (x - 6)(x + 5)(x - 9)

To find the zeros of this function, we set f(x)=0 and solve for x.

(x - 6)(x + 5)(x - 9) = 0

This implies that:

(x - 6) = 0 \: or \: (x + 5) = 0 \: or \: (x - 9) = 0

We solve for x to get:

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3 0
2 years ago
Can someone help me?
Lana71 [14]

Answer:

I'm not sure from my answer but I'm going to try

A =  { a^2  -  4  = 0 }

A = { a^2  = 0+ 4 }

A = { a^2  = 4}

Take root of both sides

A = {a = 2}

A = {2}

B = { -2, -1, 0, 1, 2}

C = { 1, 2, 3, 4, 5, 6,7}

i) A\B

= {2} \ {-2,-1,0,1,2}

= ⌀ ( "null set" )

ii) (A\B) \C

= ( {2} \ {-2,-1,0,1,2} ) \ C

= ⌀ \ C

= ⌀ \ { 1, 2, 3, 4, 5, 6,7}

= ⌀ ( "null set" )

iii) (A ∪ B) \ C

= ( { 2 } ∪ { -2, -1, 0, 1, 2} ) \ C

= { -2, -1, 0, 1, 2} \C

= { -2, -1, 0, 1, 2} \ { 1, 2, 3, 4, 5, 6,7}

= { -2, -1, 0 }

iv) ( A\B) ∩ ( A\C)

= (  { 2 } \ {-2,-1,0,1,2} ) ∩ ( { 2 } \ { { 1, 2, 3, 4, 5, 6,7} )

= ⌀ ∩ ⌀

= ⌀

v) ( A ∩ B ) \ C

= ( { 2 }  ∩  { -2, -1, 0, 1, 2 } ) \ C

= { 2 } \ { 1, 2, 3, 4, 5, 6, 7 }

= ⌀ "null set"

7 0
2 years ago
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Elena L [17]

<u><em>Answer:</em></u>

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<u><em>Explanation:</em></u>

<u>Before solving the problem, let's define each of the given theorems:</u>

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<u>2- SAS (side-angle-side):</u> This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

<u>3- ASA (angle-side-angle):</u> This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle

<u>4- AAS (angle-angle-side):</u> This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle

<u>Now, let's check the given triangles:</u>

We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

This means that the two triangles are congruent by <u>SAS</u> theorem

Hope this helps :)

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Answer:

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Step-by-step explanation:

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Answer:

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