This should be a rotation!
The first step to solving this is converting these mixed numbers into improper fractions. You would do that by multiplying the denominator by the whole number and adding the numerator to that number; this number replaces the numerator. It would look something like this:
1 8/10 --> 18/10
2 2/5 --> 12/5
Now, to subtract the second fraction from the first one, the denominators of both fractions must be the same. We can make them the same by multiplying the second fraction by 2:
12/5 * 2/2 = 24/10
Now we can set up the equation as:
18/10 - 24/10 = -6/10 --> -3/5
The answer is negative 3/5.
I hope this helps.
Yes it is a function
Y=x(x-1)
X(x-1)
X to the 2nd power -1x
Hope that’s helps
If Gavin got 11 sweets, then the new ratio would be: 11:44:11
Colin got 44 sweets.
Complete Question
The complete question is shown on the first uploaded
Answer:
is not a solution of the differential equation
is not a solution of the differential equation
is not a solution of the differential equation
Step-by-step explanation:
The differential equation given is 
Let consider the first equation to substitute



So


So

This means that
is not a solution of the differential equation
Let consider the second equation to substitute



So

So

This means that
is not a solution of the differential equation
Let consider the third equation to substitute



So

So
This means that
is not a solution of the differential equation