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3 years ago

part b: is the point (−2, 5) included in the solution area for the system? justify your answer mathematically. (4 points)

Mathematics

1 answer:

tatiyna3 years ago

7 0

We need the equations of the system. They're probably in part-a, or maybe even before both parts.

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3 years ago

What is the greatest common factor of 8 and 9

ExtremeBDS [4]

I believe the answer is 1. One is the only number that can go into both 8 and 9.

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2 years ago

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A box shaped figure like a rectangular prism has a length of 8 inches and a width of 8 inches its volume is 512 cubic inches. wh

tamaranim1 [39]

Answer

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Step-by-step explanation:

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Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

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3 years ago

Pls help me i need this or i will get grounded for a week

Pavlova-9 [17]

Answer: B !

Step-by-step explanation:

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3 years ago

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