I’m pretty sure it’s w^25
Given:
Composite figure.
The figure splitted into two shapes.
One is vertical cuboid and other is horizontal cuboid
To find:
Total surface area of the figure
Solution:
<u>Vertical cuboid:</u>
Length = 14 inches
Width = 12 inches
Height = 24 inches
Surface area = 2(lw + wh + lh)
= 2(14 × 12 + 12 × 24 + 14 × 24)
= 2(168 + 288 + 336)
Surface area = 1584 square inches
<u>Horizontal cuboid:</u>
Length = 14 inches
Width = 10 inches
Height = 30 - 12 = 18 inches
Surface area = 2(lw + wh + lh)
= 2(14 × 10 + 10 × 18 + 14 × 18)
= 2(140 + 180 + 252)
Surface area = 1144 square inches
Total surface area = 1584 + 1144
= 2728 square inches
The total surface area of the figure is 2728 square inches.
Answer:
1 3/5
Step-by-step explanation:
Anything larger than 1 multiplied by 3 1/4 would result in a number more than 3 1/4.
When the football is 81 feet high, it will be √ 3 / 8 seconds
<h3>Function</h3>
Function relates input to output. Therefore,
Therefore,
t = number of seconds
h(t) = - 16t² + 75
h(t) = 81 ft
Therefore,
81 = - 16t² + 75
- 16t² = 81 - 75
- 16t² = 6
divide both sides by -16
t² = 6 / -16
t² = - 3 / 8
square root both sides
t = √ 3 / 8 seconds
learn more on function here: brainly.com/question/4418459
Answer:
- perimter of original rectangle = <u>17. 6 mm</u>
- side length of the enlarged rectangle = <u>23. 22 mm</u>
- perimeter of the enlarged rectangle = <u>95. 04 mm</u>
Step-by-step explanation:
<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>
- Length of original rectangle = 4.5 mm
- Width of original rectangle = 4.3 mm
<em>perimeter = 2 × ( length + width)</em>
= 2 × ( 4.5 + 4.3)
= 2 × 8.8
= 17. 6 mm
<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>
- Width of original rectangle = 4. 5 mm
- Width of enlarged rectangle = 24.3 mm
Enlargement factor = 24.3 / 4.5
= 5.4
- Length of original rectangle = 4.5 mm
- Enlargement factor = 5.4
Side length of enlarged rectangle
= original length × Enlargement factor
= 4.3 × 5.4
= 23. 22 mm
<u>PERIMTER OF ENLARGED RECTANGLE</u>
= 2 × ( enlarged ength + enlarged breadth)
= 2 × (23. 22 + 24. 3 )
= 95. 04 mm
