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rewona [7]
3 years ago
9

Find an equation of the circle that has center (-4, 1) and passes through (3, -5)

Mathematics
1 answer:
Lemur [1.5K]3 years ago
5 0

The general equation for a circle with center (a,b) and squared radius k is


(x-a)^2 + (y-b)^2 = k


Here we have


(x- - 4)^2 + (y -1)^2 = k


and the constant is fixed by substituting in the point we know (x,y)=(3,-5)


(x + 4)^2 + (y-1)^2 = (3+4)^2 + (-5-1)^2 = 85


Answer:


(x + 4)^2 + (y-1)^2 = 85


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See explanation

Step-by-step explanation:

<u><em>1st photo:</em></u>

x = \sqrt{15}

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x = \sqrt{15}

<u><em>2nd photo:</em></u>

(a) GEH ~ FGH ~ FEG

<em>similar triangles, use similar corners in the right order</em>

(b) \frac{FE}{GE} = \frac{GE}{EH}   AND    \frac{FH}{GH} = \frac{GH}{HE}

<em>similar triangles, use similar sides in proportion</em>

<em />

<u><em>3rd photo:</em></u>

x = 4.5 or 4 1/2

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<em />

<u><em>4th photo:</em></u>

Length of string = 118.2 ft

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