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Stolb23 [73]
3 years ago
10

The first term in a geometric series is 64 and the common ratio is 0.75. Find the sum of the first 4 terms in the series.

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

195.25

Step-by-step explanation:

Consider geometric series  S(n) where initial term is a

So S(n)=a+ar^1+...ar^n

Factor out a

S(n)=a(1+r+r^2...+r^n)

Multiply by r

S(n)r=a(r+r^2+r^3...+r^n+r^n+1)

Subtract S(n) from S(n)r

Note that only 1 and rn^1 remain.

S(n)r-S(n)=a(r^n+1  -1)

Factor out S(n)

S(n)(r-1)=a(r^n+1  -1)

The formula now shows S(n)=a(r^n+1  -1)/(r-1)

Now use the formula for the problem

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6 0
2 years ago
What is (9,+9)0-2 and 158932x738995
Mekhanik [1.2K]

Answer:

117,449,953,338.

Step-by-step explanation:

(9,+9)0-2  =  0 - 2

= -2.

158932 x 738995

=  117,449,953,340

So the answer is

117,449,953,340 - 2

= 117,449,953,338.

6 0
3 years ago
I need help!!! I just need the answer for p and i also need the answer step by step!!
klasskru [66]

Answer:

  x = 18

  m = 21.2

  p = 31.8

Step-by-step explanation:

The ratio of the left-side length to the bottom-side length is the same for both triangles:

  x/11.2 = (x +27)/28

  28x = 11.2(x +27) = 11.2x +302.4 . . . . . multiply by 11.2·28

  16.8x = 302.4 . . . . . . . subtract 11.2x

  x = 18 . . . . . . . . . . . . divide by 16.8

__

The length of m can be found using the Pythagorean theorem. The sum of the squares of the legs is the square of the hypotenuse.

  x^2 +11.2^2 = m^2

  m = √(324 +125.44) = √449.44 = 21.2

__

The length of p can also be found using the Pythagorean theorem. We prefer the proportion ...

  p/27 = m/x

  p = 27(21.2/18) = 31.8

The lengths of the unknown sides in the figure are ...

  x = 18

  m = 21.2

  p = 31.8

8 0
2 years ago
A = {red, green, blue, yellow} B = {orange, purple, black, blue} Find A U B.
Kipish [7]

Answer:

A∪B={   red , green , blue , yellow , orange , purple , black }

Step-by-step explanation:

Let A and B be two subsets Then A∪B represents the union of the two subsets which means that it consists of the elements present in A or B or in both A and B.

given A={ red , green , blue , yellow }

B={ orange , purple , black , blue }

Now A∪B={   red , green , blue , yellow , orange , purple , black }

for getting above first write all the elements in A then start writing elements of B and skip those elements of b which are already present in A and write all the elements of B.

8 0
3 years ago
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Answer:

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