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max2010maxim [7]
3 years ago
10

Need help please how do you know what the coordinates are of the vertex? ​

Mathematics
2 answers:
kvv77 [185]3 years ago
4 0

Answer:

The vertex is the point (0,0)

Step-by-step explanation:

The zero, or place that the graph passes/sits on the X-Axis is at the point (0,0)

Gnom [1K]3 years ago
4 0
X= -b/2
Y coordinate= the value of x substituted into the original equation
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5/4=15/12
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How many one-half cubes with dimensions of 1/2 x1x1 fit in a unit cube?<br> 1<br> 2<br> 4<br> 6
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I got 2 but this could be wrong. Hope this helps ;D
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Simple interest ending balance $41,900 at 4% for 2 years?
VARVARA [1.3K]
<h3><u>Answer:</u></h3>

The simple interest is $3352.

<h3><u>Step-by-step explanation:</u></h3>

Using PRT/100, we can find the interest.

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<h3><u>Conclusion:</u></h3>

Therefore, the simple interest is $3352.

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What is the result of dividing 2x^3+6x^2+6x+2 by x+1
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Step-by-step explanation:

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7 0
3 years ago
12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests
Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that p = 0.12.

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so n = 18

This probability is:

P = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002

P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458

So

P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0
3 years ago
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