5k^3 - 3k + 7.-(-2k^3 + k^2 - 9)
7k^3 +k^2-3k +16
C. 7k^3 - k^2 - 3k + 16
Answer:???/ I DONT GET ITTT
Step-by-step explanation:
So we should reverse the equation to
10+10=2x
We know that 10+10 is 20
and 20 divided by 2 is 10
so x=10
Answer:

g(t) = 0
And
The differential equation
is linear and homogeneous
Step-by-step explanation:
Given that,
The differential equation is -

![e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0](https://tex.z-dn.net/?f=e%5E%7Bt%7Dy%27%20%2B%20%289t%20-%20%5Cfrac%7B1%7D%7Bt%5E%7B2%7D%20%2B%2081%20%7D%20%29y%20%3D%200%5C%5Ce%5E%7Bt%7Dy%27%20%2B%20%28%5Cfrac%7B9t%28t%5E%7B2%7D%20%2B%2081%20%29%20-%201%7D%7Bt%5E%7B2%7D%20%2B%2081%20%7D%20%29y%20%3D%200%5C%5Ce%5E%7Bt%7Dy%27%20%2B%20%28%5Cfrac%7B9t%5E%7B3%7D%20%2B%20729t%20%20-%201%7D%7Bt%5E%7B2%7D%20%2B%2081%20%7D%20%29y%20%3D%200%5C%5Cy%27%20%2B%20%5B%5Cfrac%7B9t%5E%7B3%7D%20%2B%20729t%20%20-%201%7D%7Be%5E%7Bt%7D%28t%5E%7B2%7D%20%2B%2081%29%20%7D%20%5Dy%20%3D%200)
By comparing with y′+p(t)y=g(t), we get

g(t) = 0
And
The differential equation
is linear and homogeneous.
We have that
case 1) 2x3 + 4x -----------> <span>C. cubic binomial
</span>The degree of the polynomial is 3----> <span>the greater exponent is elevated to 3
</span>the number of terms is 2
<span>
case 2) </span>3x 5 + 3x 4 + x 3--------> <span>A. Quintic trinomial
</span>The degree of the polynomial is 5----> the greater exponent is elevated to 5
the number of terms is 3
<span>
case 3) </span>x 2 + 3----------> <span>B. quadratic binomial
</span>The degree of the polynomial is 2----> the greater exponent is elevated to 2
the number of terms is 2
<span>
case 4) </span>2x 2 + x − 5 A------------> D. quadratic trinomial
The degree of the polynomial is 2----> the greater exponent is elevated to 2
the number of terms is 3