Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
Answer:
-85
Explanation:
Given the mathematical expression:

First, we recall the product of signs.

So, first, we open the bracket:

We then simplify:

The result is -85.
Answer:
A) 10
Step-by-step explanation:
In the US, a number in scientific notation will have a mantissa (a) such that ...
1 ≤ a < 10
That is, the value of "a" must be between 1 and 10 (not including 10).
_____
<em>Comment on alternatives</em>
In other places or in particular applications (some computer programming languages), the standard form of the number may be a×10^n with ...
0.1 ≤ a < 1
In engineering use, the form of the number is often chosen so that "n" is a multiple of 3, and "a" is in the range ...
1 ≤ a < 1000
This makes it easier to identify and use the appropriate standard SI prefix: nano-, micro-, milli-, kilo-, mega-, giga-, and so on.
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So the manufacturers can make more money out of every box. It's not about the consumers, it's always about money.