Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell
(2.5 m/s) x (45 s) = 112.5 meters .
If it wound up only 40 meters underwater, then it must have fallen
(112.5 m - 40 m) = 72.5 meters
from its storage position on the big cruise ship,
before it ever reached the water.
Since it was falling at the rate of 2.5 m/s, it took
(72.5 m) / (2.5 m/s) = 29 seconds
to get down to the water surface after it started dropping.
Answer: x = 64
Step-by-step explanation:
70 = 1/2((5x+10)-(3x-2)
(remove the inner bracket)
70 = 1/2(5x+10-3x+2)
(transfer 1/2 to LHS)
70*2 = 2x + 12
140 = 2x+12
(transfer 12 to LHS)
140 - 12 = 2x
128 = 2x
(transfer 2 to LHS)
128/2 = x
=>x = 64
hope it helps
Solve for x the. You can find your answer from there.
1.
Since ABCD is a rectangle, then
angleABE = 90 degrees
angle ABE + angle BEA + 41 = 180
Substitute the known and solve for angle BEA
angle BEA + 41 = 90
angle BEA = 49 degrees
But,
x + angleBEA + 61 = 180 (angles in a straight line)
x = 180 - 61 - 49
x = 70 degrees
2.
triangle XYZ is equilateral, meaning all angles in it are the same, each 60 degrees.
Therefore,
Angle YZX = 60
But Angle YZX = x + 32 (exterior angles equal to the sum of the two opposite interior angles)
60 = x + 32
Therefore,
x = 28 degrees
3.
Angle QPR = Angle QRP (equal oppo sides, equal opposite angles)
Therefore, 2angleQRP + 64 = 180 (angle sum of a triangle)
Angle QRP = 58 degrees
But angle QRP = x + 35 (exterior angles equal to the sum of the two opposite interior angles)
58 = x + 35
x = 23 degrees