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2 years ago

Which is the best estimate of StartRoot 47 EndRoot to the nearest tenth?

Mathematics

2 answers:

Lostsunrise [7]2 years ago

8 0

Answer:

The answer would be 6.8 or A

Step-by-step explanation:

Why? because its the closest option the the estimate after you round it to the nearest tenth.

PtichkaEL [24]2 years ago

7 0

Answer:

<em>Which is the best estimate of StartRoot 47 EndRoot to the nearest tenth? 6.8.</em>

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

Read 2 more answers

Does anyone know the answer?

motikmotik

Answer:

We conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

Step-by-step explanation:

From the given right-angled triangle,

Base = p+1

Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

$=\frac{1}{2}\left(p+1\right)\left(2p-6\right)$

Factor 2p-6: 2(p-3)

$=\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}$

Divide the number: 2/2 = 1

$=\left(p+1\right)\left(p-3\right)$

$\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

$=pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)$

$=pp-3p+1\cdot \:p-1\cdot \:3$

$=p^2-2p-3$

Therefore, we conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

3 0

2 years ago