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4 years ago

6

Ms. Eskew's class had a class average of 89 % on their Math test. How would this be written as a ratio? A. 11:100 B. 89:100 C. 7

8:100 D. 100:89

1 answer:

Anuta_ua [19.1K]4 years ago

7 0

Answer: 89:100

Step-by-step explanation:

89% out of a possible 100%

So, ratio will be 89:100

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Answer:

x=31

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a pound of chocolate costs 8 dollars. Felipe buys p pounds. write an equation to represent the total cost c that felipe pays

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Answer:

c=8p

Step-by-step explanation:

So, we know that 1 pound of chocolate will cost $8. Felipe is going to buy "p" pounds of chocolate, and "p" means "any number"; so Felipe is going to buy any number of pounds of chocolate.

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3 years ago

Anne can make 6 headbands 3/5 from meters of cloth. Which expression shows the amount of cloth needed to make 1 headband? What i

Marina CMI [18]

The amount of cloth needed to make 1 headband is 10 meters.

<h3>Unit value</h3>

Number of headbands Anne made = 6

Total clothes used = 3/5 meters

Cloth needed to make 1 headband = Number of headbands Anne made / Total clothes used

= 6 ÷ 3/5

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= (6 × 5) / 3

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2 years ago

A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

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4 years ago

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