<u>Given </u><u>:</u><u>-</u>
- The slope of the line through points (3,y) and (4,10) is 7 .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
As we know that the slope of the line is difference of ordinate divided by the difference of absicca as ,
m = y -10 / 3 - 4
7 (-1) = y -10
-7 = y -10
y = 10 -7
y = 3
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>3.</u>
parallel lines have the same slope
The slope-intercept form of a linear equatio is y=mx+b, where m stands for the "slope of the line" and b stands for the "y-intercept of the line"
They give you the equation y= -5/6x+3 Notice this is already on the slope-intercept form, so in this case the slope is -5/6 and the y-intercept is 3
You want an equation of the line that is parallel to the given line. The slopes must be the same, so m=-5/6
So far we have y=-5/6x + b
We don't have b yet but that can be found using the given point (6,-1) which tells you that "x is 6 when y is -1"
Replace that on the equation y=-5/6x + b and you get
-1 = (-5/6)(6) + b
-1 = -5 +b
4 = b
b = 4
We found b, or the y-intercept
Go back to the equation y = -5/6 x + b and replace this b with the b we just found
y = -5/6x + 4
I think it’s F
Hopefully it’s right
