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Crank
3 years ago
11

There is a bag filled with 4 blue and 5 red marbles.

Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer:

25

/81

Step-by-step explanation:

5/9 marbles are red

5/9 is the chance for getting one marble. However, twice, you need to multiply it by itself.

The answer is 25/81

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"Quick question.
givi [52]
Based on the given figure of a plate above, the inner and the outer rims are called CONCENTRIC CIRCLES. By definition, concentric circles are circles having the same or common centers. And in the figure, both the outer and the inner rims have a common center. In addition, t<span>he part between two </span>concentric circles<span> of different radii is called an annulus. Hope this is the answer that you are looking for.</span>
8 0
4 years ago
Read 2 more answers
A 30 foot ladder is leaning against the side of a building and is positioned such that the base of the ladder is 21 feet from th
dem82 [27]

Answer:

21.42ft

Step-by-step explanation:

a²+b²=c² where "c" is the hypotenuse of a right triangle and "a" and "b" are the two other sides

now let's plug in the values

21²+b²=30²

b²= 30² - 21²

b²= 459

b= 21.42

3 0
3 years ago
Which ordered pairs are in the solution set of system of linear inequalities?
astra-53 [7]

Answer:

Option (3)

Step-by-step explanation:

There are two inequalities graphed in the figure attached.

1). Solid line having shaded above the solid line (passing through origin) will be represented by the equation,

y\geq -\frac{1}{2}x

2). Another dotted line having shaded area below the line will be represented by the inequality,

y

Common shaded area of these inequalities will be the solution area.

All the ordered pairs lying in this area will be the answer.

In the given options,

Ordered pairs given in Option (3) lie in the common shaded area.

8 0
3 years ago
9. Combine the radical expression, if possible.
Anastaziya [24]

Answer:

we conclude that:

3\sqrt{125}+4\sqrt{20}=23\sqrt{5}    

Hence, the last option i.e. 23\sqrt{5} is correct.                      

Step-by-step explanation:

Given the expression

3\sqrt{125}+4\sqrt{20}

Combining the radical expressions

3\sqrt{125}+4\sqrt{20}

let us first solve

3\sqrt{125}

=3\sqrt{5^3}

=3\sqrt{5^2\cdot \:5}

Apply radical rule:  \sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0

=3\sqrt{5^2}\sqrt{5}

Apply radical rule:   \sqrt{a^2}=a,\:\quad \:a\ge 0

=3\cdot \:5\sqrt{5}

=15\sqrt{5}

Thus,

3\sqrt{125}=15\sqrt{5}

similarly solving

4\sqrt{20}

=4\sqrt{2^2\cdot \:5}

Apply radical rule:  \sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0

=4\sqrt{2^2}\sqrt{5}

Apply radical rule:   \sqrt{a^2}=a,\:\quad \:a\ge 0

=4\cdot \:2\sqrt{5}

=8\sqrt{5}

Thus,

4\sqrt{20}=8\sqrt{5}

so we get

3\sqrt{125}=15\sqrt{5}

4\sqrt{20}=8\sqrt{5}

so the expression becomes

3\sqrt{125}+4\sqrt{20}=15\sqrt{5}+8\sqrt{5}        ∵ 3\sqrt{125}=15\sqrt{5} , 4\sqrt{20}=8\sqrt{5}

                        =23\sqrt{5}                   ∵ 15\sqrt{5}+8\sqrt{5}=23\sqrt{5}

Therefore, we conclude that:

3\sqrt{125}+4\sqrt{20}=23\sqrt{5}    

Hence, the last option i.e. 23\sqrt{5} is correct.                    

7 0
3 years ago
PLEASE LET ME ADD PICS BEFORE ANSWERING!!!!!!
Helen [10]
1. inconsistant. point in quadrent 2.
2. equivilant. point in quadrent 1. 
3. consistent. point on neg x-axis

Im pretty sure this is right but if not tell me

3 0
4 years ago
Read 2 more answers
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