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11111nata11111 [884]
3 years ago
12

*Will give 40 points!!* The data on the box plot describes the weight of several students in sixth grade. Which of the following

statements are true about the data set? Select all that apply.
A. The median weight of the sixth graders is 85 pounds.
B. The total range of weight is 40 pounds.
C. One-fourth of the students weigh more than 75 pounds.
D. One-fourth of the students weight between 90 and 101 pounds.
E. One-fourth of the students weight less than 75 pounds.
F. One-half of the students weigh between 75 and 90 pounds.

Remember: This is a select all that apply question! <3​

Mathematics
2 answers:
Tanya [424]3 years ago
8 0

A,C,F

Step-by-step explanation:

Orlov [11]3 years ago
3 0

Answer:

A, D, E, F

Step-by-step explanation:

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-7 and 21

Step-by-step explanation:

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if y=-7,

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3 years ago
If g(x)= -(3/(4x)) , find g(g(x)) please show work.
ivann1987 [24]

Answer:

g(g(x)) = x

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4 0
3 years ago
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Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of d^2y/dx
nikdorinn [45]

Answer:

Differentiation will give you the gradient for the tangent at any point, and you use the product rule whenever a function can be thought of as two functions multiplied together.

If

f

(

x

)

=

g

(

x

)

×

h

(

x

)

then

f

'

(

x

)

=

g

'

(

x

)

h

(

x

)

+

g

(

x

)

h

'

(

x

)

so if

y

=

x

×

sin

x

then

d

y

d

x

=

1

×

sin

x

+

x

×

cos

x

=

sin

x

+

x

cos

x

We know that

x

=

π

2

, so the gradient is

m

=

sin

(

π

2

)

+

π

2

cos

(

π

2

)

=

1

+

π

2

×

0

=

1

Therefore, we can say that

y

=

m

x

+

c

y

=

(

1

)

x

+

c

y

=

x

+

c

So all we really need to find now is the value for

c

, the

y

intercept. We do this by working out a point

(

x

,

y

)

on the graph. We are already given that

x

=

π

2

, so

y

=

x

sin

x

=

π

2

sin

(

π

2

)

=

π

2

×

1

=

π

2

∴

(

x

,

y

)

=

(

π

2

,

π

2

)

Now we substitute this into the equation we already have for the tangent,

y

=

x

+

c

,

(

x

,

y

)

=

(

π

2

,

π

2

)

π

2

=

π

2

+

c

c

=

π

2

−

π

2

=

0

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y

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x

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c

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+

(

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y

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sin

x

at

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