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Minchanka [31]
3 years ago
6

What is the fraction 12 30 in simplest form? O 15 3 10

Mathematics
1 answer:
Ahat [919]3 years ago
3 0

Answer:

2/5

Step-by-step explanation:

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Find the equation of the line that passes through the point (−3, −4) and is parallel to the line that passes through the points
Dimas [21]

Answer:

y = -\frac{1}{3}x - 5

Step-by-step explanation:

To write the equation of a line use the point slope formula y - y_1 = m(x-x_1). Find m by using the slope formula with the points.

m = \frac{y_2-y_1}{x_2-x_1} = \frac{1--3}{-5-7} =\frac{4}{-12} =-\frac{1}{3}

Since the line is parallel, it will have the same slope.

Substitute m = -1/3 and (-3,-4).

y --4 = -\frac{1}{3}(x --3)\\y + 4 = -\frac{1}{3}(x+3)\\y +4 = -\frac{1}{3}x - 1\\y = -\frac{1}{3}x - 5

8 0
4 years ago
Factor this expression.
scoundrel [369]
The factor will result to answer which is D
5 0
3 years ago
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Consider the linear function that is represented by the equation y = negative 10 x + 6 and the linear function that is represent
Vilka [71]

Answer: The function that is represented by the equation y = negative 10 x + 6 has a steeper slope and a greater y-intercept.

Step-by-step explanation: I took the unit test on edge hoped this helped <3

8 0
4 years ago
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If a particular set of data is approximately normally distributed, we would find that approximately A) 2 of every 3 observations
Kryger [21]

Answer:

A) No

B) No

C) Yes

Step-by-step explanation:

A)  2 out of three observations is equal to

2/3  = 0.67    or  67 %

We know tha the interval

[μ  -  σ/2 ,  μ + σ/2]  is approximately 68.3 % of the values

Therefore 2 out of 3 would not fall in that interval

B)

4 out of  5   is  4/5    = 0,8     or 80 %  If we  examine the interval

[μ  -  σ ,  μ + σ ]   which is approximately 95. Then value 4/5  ( 0,8)

Therefore 0,8 is out of the interval

C) 19/20 = 0,95     or 95 % is almost exact the value for the interval

[μ  -  1.5σ ,  μ + 1.5σ ]  That value is inside  μ - 2σ , μ + 2

8 0
3 years ago
Graph each equation y=7x-7<br><img src="https://tex.z-dn.net/?f=y%20%3D%207x%20-%207" id="TexFormula1" title="y = 7x - 7" alt="y
Dafna1 [17]

to graph a LINEar equation, since it's just a straight line, recall, to draw a straight line all you need is two points.

so we can just pick two random "x" values, hmmmmm say x = 0, what's "y"?

y = 7(0)-7 => y = -7....................................... so that gives us the point (0, -7)

hmmm x = 2, what is "y"?

y = 7(2) - 7 => y = 14-7 => y = 7................. so we get the point (2, 7).

then just plot those, and run a line through them.

6 0
3 years ago
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